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6,35 moles of S contain 38,24059444195.10e23 sulfur atoms.
0.6 X Avogadro's Number = about 3.6 X 1023.
H2O: 44g x 1 mol/18 g = 2.44 moles and 2.44 moles x 6.02x10^23 atoms/mole = 1.5x10^24 atomsS-32: 44g x 1mol/32g = 1.375 moles and 1.375 moles x 6.02x10^23 atoms/mole = 8.3x1^23 atomsO-16: 44g x 1 mol/16g = 0.6875 moles and 0.6875 moles x 6.02x10^23 atoms/mol = 4.2x10^23 atomsH-1: 44g x 1mol/1g = 44 moles and 44 moles x 6.02x10^23 atoms/mole = 2.6x10^25 atoms
4H2SO4 = 4*(2(H)+1(S)+4(O)) = 4*(2+1+4) = 4*7 = 28 There are 28 atoms in 4 moles of H2SO4.
6,5 grams of sulfur S are equal to 0,203 moles.
6,35 moles of S contain 38,24059444195.10e23 sulfur atoms.
The reaction equation is 2 NaHCO3 + H2SO4 = 2 CO2 + 2H2O + Na2SO4. This means that for every mole of sulfuric acid, two moles of NaHCO3 are needed. 150 grams of H2SO4 is 1.53 moles, so 3.06 moles of NaHCO3 are required.
0.6 X Avogadro's Number = about 3.6 X 1023.
Full formal set up. 48.096 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S)(1 mole S atoms/6.022 X 1023) = 1.4997 moles of sulfur atoms ---------------------------------------
multiply 5 with 6.02x10x23 and the answer will be 3.01x10
You will need to convert to moles, and then atoms. Here is the equation: (5.10 grams over one) times (1 mol S over 32.06 g S) times (6.022 X 10 23 atoms over 1 mol S) the last part of the equation is read six point zero two two times ten to the twenty third.
H2O: 44g x 1 mol/18 g = 2.44 moles and 2.44 moles x 6.02x10^23 atoms/mole = 1.5x10^24 atomsS-32: 44g x 1mol/32g = 1.375 moles and 1.375 moles x 6.02x10^23 atoms/mole = 8.3x1^23 atomsO-16: 44g x 1 mol/16g = 0.6875 moles and 0.6875 moles x 6.02x10^23 atoms/mol = 4.2x10^23 atomsH-1: 44g x 1mol/1g = 44 moles and 44 moles x 6.02x10^23 atoms/mole = 2.6x10^25 atoms
16 g O x 1 mol/16 g = 1 mole and 1 mole = 6.02x10^23 atoms of O8g S x 1 mol/32 g = 0..25 moles S and then 0..25 moles x 6.02x10^23 atoms/mole = 1.5x10^23 atoms of S, or rounding to 1 significant figure, you have 2x10^23 atoms of S
4H2SO4 = 4*(2(H)+1(S)+4(O)) = 4*(2+1+4) = 4*7 = 28 There are 28 atoms in 4 moles of H2SO4.
One mol is 6.02214179×1023 so about 3*10-4 (3 times ten to the minus 4) moles
Which sample contains the greatest number of atoms. A sample of Al that contains 8.18E+23 atoms or a 5.16 mole sample of S?The sample of______ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of S to atoms of S.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.16 moles of S to atoms of S:atoms S=5.16 mol S6.02 x 1023 atoms S= 3.11E+24 atoms S1 mol SMultiply by atoms per mole. Moles cancel out.The sample of Al contains 8.18E+23 atoms.Since 3.11E+24 is larger than 8.18E+23, the sample of S contains the greatest number of atoms.
There are more atoms of sulfur in 16 grams than there are atoms of iron in 56 grams.