Balanced equation.
2C8H18 + 25O2 -> 16CO2 + 18H2O
5.5 moles C8H18 (25 moles O2/2 moles C8H18)
= 68.75 moles O2 needed
40
The answer is 8 moles CO2.
how many moles are in 95.0 gram of octane?
C8H18. I assume you mean how many moles octane in 16 grams. 16 grams C8H18 (1 mole C8H18/114.224 grams) = 0.140 moles octane
6,49 moles of water are obtained.
9
The answer is 8 moles CO2.
There are eight carbon atoms and eighteen hydrogen atoms.
how many moles are in 95.0 gram of octane?
C8H18. I assume you mean how many moles octane in 16 grams. 16 grams C8H18 (1 mole C8H18/114.224 grams) = 0.140 moles octane
Absolutely none, as there is no oxygen in hydrogen cyanide. Its formula is HCN--one atom each of hydrogen, carbon and nitrogen.
6,49 moles of water are obtained.
5 moles
12 moles
Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
9
Moles of carbon dioxide = grams/amu of carbon dioxide. Moles = 19g/44amu Moles of carbon dioxide = .432
Seventeen moles of hydrogen correspond to 204,75.10e23 atoms.