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How many moles of hydrogen must react to produce 68 grams of ammonia?
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How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
How many grams of H2 are needed to produce 10.06 g of NH3?
The formula reaction for NH3 when using N2 and H2 is: (N2)+3(H2) ---> 2(NH3) Now, first step is to find the moles of the H2 reactant. This is found via (grams of reactant)/(molar mass of reactant). There are 10 grams, and the molar mass of H2 is approximately 2.016. Therefore, the equation should look like: 10/2.016. This yields a value of ~4.9606 moles of H2. Now, you use the molar ratio from the reactant to the product to determine how many moles of product were yielded. According to the reaction, three moles of H2 are required to produces 2 moles of NH3. So, the mole ratio is 2/3. Multiply the number of moles of H2 with the molar ratio to determine the moles of NH3. 4.0606 * 2/3 = 3.3071 moles of NH3. Multiply the number of moles with the molar mass of NH3 (17.0306), and voila! 3.3071 * 17.0306 = 56.3216 grams. Now, if your teacher is feeling like a stickler about significant figures, than that value should be rounded to 56 grams of NH3.
How will you prepare inorganic benzene from diborane?
Take a multiple of three moles of diborane plus a multiple of six moles of ammonia, mix them together, heat them to 300 degrees Celsius and stand by with a fire extinguisher because reacting three moles of diborane with six moles of ammonia liberates 12 moles of hydrogen.
How many moles of nitrogen would be needed to completely react with 12 moles of hydrogen according to the balanced equation given below?
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many moles of ammonia are produced from 12.0 moles of hydrogen?
N2 + 3H2 -----> 2NH3 so 3 moles of hydrogen produce 2 moles of ammonia. Therefore 12.0 moles of hydrogen will produce 8 moles of ammonia.
How many moles of ammonia are needed to produce 3.5 mole of nitrogen?
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
If .3 mole of N2 are reacted with .6 mole of H2 what mass of NH3 could form the formula N2 plus 3 H2 makes 2 NH3 The answer to the problem is 6.8 but don't know how to get that?
First you have to find the limiting reactant. You have .3 moles of nitrogen and .6 moles of hydrogen, but you don't know which one is going to run out first.In any of these stoichiometry problems, you need to write down the formula:N2 + 3H2 → 2NH3Take both nitrogen and hydrogen and figure out how much ammonia is made alone..6 moles Hydrogen ÷ 3 moles hydrogen × 2 moles ammonia = .4 moles ammonia made.3 moles Nitrogen ÷ 1 mole nitrogen × 2 mole ammonia = .6 moles ammonia madeNow you figured out that hydrogen is the limiting reactant and the nitrogen is the excess because less ammonia is made using hydrogen. This measurement is what you will be using for the rest of the problem.Take the limiting reactant and use stoichiometry to find how much ammonia can be made.You could start with .6 moles of hydrogen and do the same conversion as above, but add the step of converting to grams. Or, since you already found out that .4 moles ammonia is made, just convert it to grams. The molecular mass of ammonia is 17.0 grams..4 moles ammonia × 17.0 grams = 6.8 grams ammonia
How many moles of nh3 are produced when 1.8 moles h2 reacts?
N2 + 3H2 ---> 2NH3 so 3 moles of Hydrogen produces 2 moles of ammonia. Thus 1.8 moles will produce 1.8/3 x 2 = 1.2 moles of ammonia.
If formula for ammonia is NH what is the mass of 3 moles of ammonia would be in grams?
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?
The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2
What has more atoms 17.031 grams of ammonia or 72.922 grams of hydrogen chloride?
Molar mass of ammonia is 17.031 whereas molar mass of hydrogen chloride (or hydrochloric acid) is 36.461. Hence if given masses, there is 1 mole ammonia and 2 moles HCl. Hence there is more number of hydrogen chloride.
The mass of 3 moles of ammonia would be how many grams?
3 moles of ammonia is 51grams. One mole is 17 grams.
The formula for ammonia is NH3 the mass of 3 moles of ammonia would be how many grams?
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
Mass of 3 moles of ammonia would be?
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
400.0 grams of ammonia react with 56.0 moles of sulfuric acid to produce ammonium sulfate?
44.1-44.5 -Apex
How many grams of H2 are needed to produce 13.14g of NH3?
The balanced equation for the formation of NH3 is N2 + 3 H2 --> 2 NH3. 13.64 grams of ammonia is equal to .801 moles. Then 1.2015 moles of hydrogen are needed, or 2.42 grams.
