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How many moles of kclo3 must be used to produce 6 moles of oxygen gas?
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How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many moles potassium chlorate must be used to produce 6 moles of oxygen gas?
We need 3 moles of potassium perchlorate.
How many moles of potassium chlorate must be used to produce 6 moles if oxygen gas?
Four moles of potassium chlorate are needed.
What is 16 grams of oxygen how many moles?
16 grams of oxygen how many moles is 0,5 moles.
How many oxygen atoms are there in one molecule of potassium chlorate?
Potassium chlorate (KClO3) has 3 oxygen atoms.
How many moles of potassium chlorate (KClo3) must be used to produce 6 moles of oxygen?
2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.
How many moles of potassium chlorate produce 6 moles of oxygen gas?
The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.
How many moles of oxygen are produced from twelve moles of potassium chlorate?
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
How many moles of oxygen are produced when 7.5 moles of potassium chlorate decompose completely?
2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
How many moles of oxygen are produced from 14 moles of potassium chlorate?
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
How many moles of KCl will be formed from 0.440 moles of KClO3?
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
How many moles of KClO3 on decomposition give 1 mole of oxygen?
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
How many moles of oxygen would be produced by 1.2 moles of KClO3?
2 to 3, because of the balanced equation:2 KClO3 --> 2 KCl + 3 O2
A How many moles of O2 were produced b What percent of the mixture was KClO3 and KCl?
A 1.80-gram mixture of potassium chlorate, kclo3, and potassium chloride, kcl, was heated until all of the kclo3 had decomposed the liberated oxygen, after drying, occupied 405 ml at 25C when the barometric pressure was 745 torr. This is the problem and the questions were... a. How many moles of O2 were produced? b. What percent of the mixture was KClO3? KCl? Please help!!
When 46.0 g KClO3 is heated 12.1 g O2 is formed how many grams of KCl is also formed?
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
How many grams of potassium chloride are produced if 25 grams of potassium chlorate decompose into potassium chloride and oxygen?
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
