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What volume will 3.56 moles of methane occupy at STP?
This volume is 79,79 litres.
How many moles of methane are presentin 5.6L of the gas at stp?
0.25 moles
How many moles of of hydrogen gas occupy 112L at stp?
Ideal gas equation. PV = nRT ===============
Description of 16.0 grams of methane?
I mole - 16g of methane is 1 mole. At STP it would occupy 22.4 liters
What volume does 0.685 moles of gas occupy at stp?
The volume is approx. 15,35 litres.
What volume will 3.56 moles of methane occupy at STP?
This volume is 79,79 litres.
How many moles of methane are presentin 5.6L of the gas at stp?
0.25 moles
How many moles of of hydrogen gas occupy 112L at stp?
Ideal gas equation. PV = nRT ===============
Description of 16.0 grams of methane?
I mole - 16g of methane is 1 mole. At STP it would occupy 22.4 liters
What volume does 0.685 moles of gas occupy at stp?
The volume is approx. 15,35 litres.
At stp how many moles of helium would occupy 1.00l?
At standard temperature and pressure, 1 mole of any gas will occupy 22.4 liters. Set up a direct proportion of 22.4 liters/1 mole = 1 liter/x moles and solve for x. You get 0.045 moles.
What volume does 0.50 mole of NH3 at STP occupy?
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
How many molecules are in 30 liters of methane (CH4) at STP?
How many molecules are in 30 liters of methane (CH4) at STP
How do you calculate the number of liters of 3.30 moles of helium at stp?
1 mole occupies 22.414 liters So, 3.30 moles will occupy 73.966 liters.
How many moles are present in 8.4 liters of nitrous oxide at STP?
8,4 liters of nitrous oxide at STP contain 2,65 moles.
How many moles are contained in 16.8 L of Xe gas at STP?
16,8 L of Xe gas at STP is equivalent to 0,754 moles.
What volume is occupied by 55 g of methane CH4 (g) at STP?
The easiest way to approach this is to remember molar volume: one mole of every (ideal) gas will occupy 22.4 liters at STP - a gas occupies 22.4 L/mol. Since we know that, we can set up a simple proportion that follows the thought process: if one mole of a gas occupies 22.4 liters (at STP), then 2.88 grams of methane occupies x liters. But before we do that, we have a problem: the measurement given is in the wrong units - it is in grams when molar volume is in moles. Therefore, we first need to convert 2.88 grams of methane to moles. To do this, we need the molar mass of the compound - the sum of all the atomic masses involved. Carbon = 12.0 grams Hydrogen = 1.01 grams × 4 atoms = 4.04 grams ------------------------------------------------------------- Methane = 16.04 grams To convert grams to moles: Grams of substance ÷ Molar mass (in grams) = Moles of substance 2.88 grams CH4 ÷ 16.04 grams CH4 = 0.180 moles CH4 Now we follow through with our proportion: 22.4 L/1 mol = x L/.180 mol x = 4.03 L 2.88 grams of methane occupies 4.03 liters at STP
