Since we know that one mole of any gas at STP is equal to 22.4 L we can multiply 135L by the following conversion: 1 mole/22.4L. When you set up the problem it looks like this:
(135L)x 1 mole/22.4L =6.03 moles of oxygen gas
The liters cancel out and you are left with moles as your units. Remember, if you have liters and want moles, divide by 22.4 liters; if you have moles and you want liters you multiply by 22.4 liters.
1mole of 02= 32gm of O2
(and at NTP/STP every gases having molar mass have equal volume(V)
i.e V=22.4Litres )
since O2 is a gas. So, its volume will 22.4L
i.e 32gm of O2 =22.4L
so, 1L = 32/22.4 gm of O2
so, finally
135 L = 32/22.4 * 135 gm,
which is the required answer....
6.02
Assuming ideal behaviour, 1 mole of any gas occupies 22.4L at STP. So, moles of 10L = 10/22.4 moles = 0.4464 moles
at stp 1 mole of a gas contains 22.4 litres. 9.1/22.4= .40625 moles o2. 1 mole of a gas contains 6.022E23 molecules so .40625 moles x 6.022E23 = 2.4464325E23 molecules, but you have to multiply by two due to it being diatomic, so answer x 2 = 4.892875E23 molecules
Because oxygen gas (O2) has a molar mass of 32g/mol, 11.3 g * 1/32 mol/g gives about .35 moles. An ideal gas has a volume of 22.4 L/mol at STP, so 11.3 g O2 would have a volume of 7.91 L at STP.
At standard temperature and pressure (STP), one mole of a gas is 22.4L. So, in order to determine how many moles of O2 are in 30L, you do the following: multiply 30L O2 x 1mol O2/22.4L O2, which equals 1.34mol O2.
At STP 2.21 L CO2 is 0.0987 moles of CO2 since 1 mole = 22.4L. One mole CO2 contains 1 mole of C so there are 0.0897 moles of C. Grams of C = 0.0987mole x 12g/mole = 1.18 grams.
3.058
If the density of oxygen atSTP is 1,429 g/L the mass of 180 L is 257,22 g.If the mole of oxygen (O2) is 15,999 g the number of moles is 16,077.
0.67 mol
A cubic decimeter is a liter, so we're talking 50L of oxygen gas at STP. 1mol of any gas at STP occupies 22.4L of space, so 50/22.4 = about 2.2mol of oxygen.
The amount of oxygen is 0,067 moles.
0.25 moles
8,4 liters of nitrous oxide at STP contain 2,65 moles.
16,8 L of Xe gas at STP is equivalent to 0,754 moles.
No. of moles = mass/relitive molecular mass in this case = 10/16 = 0.625 so that's 0.625 of a mole and a mole of anything contains 6.022 x 1023 atoms = 3.76 x 1023 atoms in 10g of oxygen.
The answer is 2,68 moles.
The answer is 0,2675 moles.
Approx 0.223 moles.