449 (g K) / 39.1 (g/mol K) = 11.5 mol K
449 g K x 1 mole K/39 g K = 11.5 moles (3 sig figs)
Potassium bromide is KBr, the atomic mass of this compound is ca. 119.1. no.moles = mass/relitive molecular mass, so in this case that's 245/119.1 = 2.057 moles of KBr.
there are two moles produced in potassium nitrate.
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
Potassium (chemical symbol K) has atomic number 39.1. Amount of K in 449g sample = 449/39.1 = 11.5mol There are 11.5 moles of potassium in a 449g sample.
449 g K x 1 mole K/39 g K = 11.5 moles (3 sig figs)
6.81 X 1024 atoms potassium (1 mole K atoms/6.022 X 1023) = 11.3 moles of potassium atoms ========================
Potassium bromide is KBr, the atomic mass of this compound is ca. 119.1. no.moles = mass/relitive molecular mass, so in this case that's 245/119.1 = 2.057 moles of KBr.
12 g of potassium is equivalent to 0,307 moles.
there are two moles produced in potassium nitrate.
34,7 moles of potassium 1 356,7 g.
How many moles of atoms are contained in 382 g Co
Four moles of potassium chlorate are needed.
We need 3 moles of potassium perchlorate.
The answer is 1 mole potassium chlorate.
You did not describe the amount of potassium bicarbonate amount in grams in your question. But if you are about 1 gram of potassium bicarbonate it will be 0.0099 moles in one gram of potassium bicarbonate. 0.0199 moles in 2 grams of potassium bicarbonate.