This is specific to a reaction that must be provided
The coefficients in a balanced chemical equation shows how many moles of each reactant is needed in order for a reaction to take place. After determining how many moles of each reactant is required, you would convert it to grams to calculate how much of each reactant is needed to form a given amount of product in a chemical reaction.
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
To answer that question we need a reaction, for example I will use this one. 2 A + 4 B --> 2 AB2 Imagine having 10 moles of A and 100 moles of B Once your 10 moles of A have been used up (along with 20 moles of B), you will be stuck with 80 B, without A, it will not react. Therefor it is limited (in this case) by the amount of A.
We need 3 moles of potassium perchlorate.
The number of moles of catalyst depends on the reaction under consideration. Compared to the substrate, about 10-2 to 10-6 times of the catalyst can be used. The lower the amount of the catalyst, the more effective it is.
234 grams
The ratio of the coefficients tells the ratio of moles of reactants used in the reaction.
The coefficients in a balanced chemical equation shows how many moles of each reactant is needed in order for a reaction to take place. After determining how many moles of each reactant is required, you would convert it to grams to calculate how much of each reactant is needed to form a given amount of product in a chemical reaction.
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
2H2 + O2 --> 2H2OAs you can see by the balanced reaction, for every 1 mole of oxygen used, 2 moles of water are formed. Also notice that for every 1 mole of oxygen used, you need 2 moles of hydrogen to produce the 2 moles of water. So in your case 110 moles of oxygen would produce 220 moles of water & would also require 220 moles of hydrogen (which you have in excess since you have 230 moles of hydrogen). So 220 moles of water are the most that can be formed.
One
Stoichiometry is used to find the molar ratios between the reactants of a chemical reaction.
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
To answer that question we need a reaction, for example I will use this one. 2 A + 4 B --> 2 AB2 Imagine having 10 moles of A and 100 moles of B Once your 10 moles of A have been used up (along with 20 moles of B), you will be stuck with 80 B, without A, it will not react. Therefor it is limited (in this case) by the amount of A.
.0104 mol
Four moles of potassium chlorate are needed.