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How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
How many moles of water will be produced from 14000 mol of hydrazine used by a rocket?
H2N---NH2 + O2 ------> 2H2O + N2 so 1 mole of hydrazine produces 2 moles of water. 14000 moles of Hydrazine thus produces 28000 moles of water.
How is stoichiometry used to calculate the amount of product produced?
Stoichiometry relates moles of reactant to moles of product, so if you have the amount of reactant in the equation, you can calculate the amount of product produced.
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
First a balanced chemical equation is needed.CH4 + 2O2 -> CO2 + 2H2OThere is a 1:1 ratio of moles between methane and carbon dioxide so the amount of moles of methane used is the exact number of moles of carbon dioxide yielded.To determine the number of moles of methane we take the amount used and divide by methane's mass which is about 16.04 g/mol.100g/ 16.04g/mol=6.234moles of methane.6.234 moles of methane are used and 6.234 moles of carbon dioxide are produced.
How many moles of H2O can be formed when 4.5 moles of NH3 react with 3.2 moles of O2 NH3 plus O2 yields NO plus H2O?
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
How many moles of water will be produced from 14000 mol of hydrazine used by a rocket?
H2N---NH2 + O2 ------> 2H2O + N2 so 1 mole of hydrazine produces 2 moles of water. 14000 moles of Hydrazine thus produces 28000 moles of water.
How is stoichiometry used to calculate the amount of product produced?
Stoichiometry relates moles of reactant to moles of product, so if you have the amount of reactant in the equation, you can calculate the amount of product produced.
How many moles of carbon dioxide are produced from the complete combustion of 100.0 grams of methane?
First a balanced chemical equation is needed.CH4 + 2O2 -> CO2 + 2H2OThere is a 1:1 ratio of moles between methane and carbon dioxide so the amount of moles of methane used is the exact number of moles of carbon dioxide yielded.To determine the number of moles of methane we take the amount used and divide by methane's mass which is about 16.04 g/mol.100g/ 16.04g/mol=6.234moles of methane.6.234 moles of methane are used and 6.234 moles of carbon dioxide are produced.
How many moles of water can be produced by burning 325g of octane in excess oxygen?
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
When the solid acid dissolves to form ions how many moles of H plus ions are produced for every mole of acid used?
10000
How many moles of H2O can be formed when 4.5 moles of NH3 react with 3.2 moles of O2 NH3 plus O2 yields NO plus H2O?
Using the molar mass of nh3, we find that we have 2.5 moles of nh3. Since 3 moles of h2o are produced per 2 moles of nh3, we see that we will produce 3.75 moles of h2o. This is equivalent to around 3.79 g.
How many molecules -not moles- of NH3 are produced from 3.07104 g of H2?
Balanced equation is N2 + 3H2 ==> 2NH33.07104 g H2 x 1 mol/1.0079 g = 1.7679 moles H2 presentmoles NH3 produced = 2/3 x 1.7679 moles = 1.1786 moles NH3 formedmolecules NH3 = 1.1786 moles x 6.022x10^23 molecules/mole = 7.098x10^23 molecules (4 sig figs based on sig figs used in 6.022x10^23)
How can balenced equations be used to calculate the volume of gases formed in chemical reactions?
The coefficients in a balanced chemical equation shows how many moles of each reactant is needed in order for a reaction to take place. After determining how many moles of each reactant is required, you would convert it to grams to calculate how much of each reactant is needed to form a given amount of product in a chemical reaction.
How many grams of iron II sulfide have to react with hydrochloric acid to generate 12 g of hydrogen sulfide?
FeS+2HCl-->FeCl2+H2S Moles of H2S produced equal to moles of FeS used. Moles of H2S=12\34=0.353mol Grams of Fes=0.353*88=31.05g
