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This solution contain 0,3 mol of sodium chloride.
The answer is 2,4 moles.
8.2mol/dm3
200/1000 x 6 = 1.2 moles
0.40 moles of sodium chloride weighs 23.4g.
Molarity = moles of solute/Liters of solution ( 22.0 ml = 0.022 Liters ) moles of solute = Molarity * Liters of solution Moles of NaCl = 0.500 M * 0.022 Liters = 0.011 moles of sodium chloride -------------------------------------------
100ml is 0.1 litres, so you need 0.1 moles of sodium chloride.
Molarity = moles of solute/Liters of solution ( find the moles ) 2.36 M NaCl = moles NaCl/5.08 Liters NaCl = 12.0 moles
0,40 moles of sodium chloride contain 23,376 g.
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
0.1 Moles
2.27