10,55 moles of water are obtained.
2H2 + O2 ---------------> 2H2O for every 2 moles of hydrogen that reacts, 2 moles of water are produced, thus a 1:1 ratio of water produced to hydrogen reacted. So:- 2.5 moles of hydrogen reacted will produce 2.5 moles of water
Each mole of butane, which has formula of C4H10, contains 10 moles of hydrogen atoms. If the butane is completely combusted, all of the hydrogen in the butane is converted in water, with the formula H2O. The amount of water vapor will accordingly be 5.50 X 10/2 = 27.5.
Since a water molecule, H2O, has exactly the same quantity of hydrogen atoms as a hydrogen molecule, H2, it follows that one mole of water can be decomposed into one mole of hydrogen gas.
0.76 mole
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
2H2 + O2 ---------------> 2H2O for every 2 moles of hydrogen that reacts, 2 moles of water are produced, thus a 1:1 ratio of water produced to hydrogen reacted. So:- 2.5 moles of hydrogen reacted will produce 2.5 moles of water
2CH3OH + 3O2 --> 2CO2 + 4H2O is the balanced equation for the combustion of methanol. It says that you get twice as many moles of water as you get carbon dioxide. 3.25 mol x 2 = 6.50 mol
Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned
Given the balanced equation C10H8 + 12O2 --> 10CO2 + 4H2O In order to find the mass in grams of CO2 that can be produced from 25.0 moles of C10H8, we must convert from moles to mass (mol --> mass conversion). 25.0 mol C10H8 * 10 molecules CO2 * 44.01g CO2 = 1.1025x104 (11025)g CO2 ------------------------- 1 molecule C10H8
H2O is water. One mole of water contains 2 moles of hydrogen atoms. Therefore, 10.7 moles of water contain 21.4 moles of hydrogen atom.
The complete combustion of any hydrocarbon, including methane, produces one water molecule for each two atoms of hydrogen in the hydrocarbon. The formula of methane is CH4; therefore, the complete combustion of one mole of methane produces two moles of H2O.
The combustion of hydrogen requires oxygen, which is supplied by the surrounding air. When hydrogen is combusted, it reacts with oxygen in the equation: 2H2 + O2 --> 2H2O with water (H2O) being the product
The reaction requires 2 moles of hydrogen gas and 1 mole of oxygen gas to produce 2 moles of water.
6 moles COULD be produced
Well if one mole of water = 2 moles of hydrogen and 1 mole of oxygen, than 2moles of water = 4 moles of hydrogen and 2moles of oxygen.
4 moles of hydrogen atoms