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The chemical formula of ibuprofen isC13H18O2 and there are no nitrogen atoms in it.
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Q: How many number of nitrogen Atoms does Ibuprofen has?
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Exactly 8.7 mol of nitrogen monoxide contains how many nitrogen monoxide molecules how many nitrogen atoms how many oxygen atoms how many total atoms of all kinds?

Multiply 8.7 by avagadros number to get the number of molecules. 8.7x6.02x1023=5.24x1024 molecules of NO. as there is 1 atom of N and one of O for each molecule there are 5.24x1024 atoms of each element. this means that the total number of atoms is 2x5.24x1024 = 1.05x1025 atoms


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There are 10 atoms in two nitric acid molecules. Namely they are two hydrogen atoms, two nitrogen atoms and six oxygen atoms.


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There are only nitrogen, oxygen atoms and no carbon atoms at all.


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In its natural state, nitrogen is diatomic and will form N2 (two bonded nitrogen atoms).


How many atoms are in 1.38 moles of nitrogen?

1.38 moles of nitrogen equal16,62110876532.1023 atoms; the molecule of nitrogen is diatomic.


How many atoms are in 1.38 mole of nitrogen?

1.38 moles of nitrogen equal16,62110876532.1023 atoms; the molecule of nitrogen is diatomic.


Nitrogen has an atomic number of 7. how many hydrogen atoms are necessary to join the nitrogen to form a stable compound?

3


What will be the ration of hydrogen atoms to nitrogen atoms in a molecule of resulting compound?

There will be three times as many hydrogen atoms as nitrogen atoms.


How many moles of ibuprofen contain 7.4x1025 atoms of Carbon?

C13H18O2 = ibuprofen 7.4 X 1025 carbon atoms (1 mole C atoms/6.022 X 1023)(1 mole ibuprofen/13 mole carbon) = 9.5 moles ibuprofen ------------------------------


How many grams of N combine with 7.05x1022 O atoms in N2O5?

The formula N2O5 shows that there are 2/5 as many nitrogen atoms as oxygen atoms in the compound. Therefore, the number of nitrogen atoms required is (2/5)(7.05 X 1022) or 2.82 X 1022 atoms. The gram atomic mass of nitrogen is 14.0067 and, by definition, consists of Avogadro's Number of atoms. Therefore, the mass of nitrogen required to react with the specified amount of oxygen to produce the specified compound is 14.0067 [(2.82 X 1022)/(6.022 X 1023] or 0.656 grams of nitrogen, to the justified number of significant digits.


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There are four nitrogen atoms in this compound (C8H10N4O2).


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