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From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
The number of atoms is seven.
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
Cyanic acid contain four atoms.
C9H804 contains a total of 12 atoms.
Assuming 0.75 g of P2O5,moles of P2O5 = 0.0053 moles1 molecule of P2O5 has 7 atoms.so reqd. no. is 2.23 X 1022.
740 grams P2O5 (1 mole P2O5/141.94 grams)(6.022 X 10^23/1 mole P2O5) = 3.14 X 10^24 atoms of P2O5
P2O5 2 atoms of phosphorous 5 atoms of oxygen ------------------------------+ 7 atoms altogether
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
There is 25.0 moles Oxygen
25x6.022x10^23=1.5x10^25p2o5=7atom7(1.5x10^25)
5, the subscript immediately after the atomic symbol O for oxygen.
Diphosphorus pentoxide has 5 oxygen atoms per molecule according to the given prefix. So, 5 moles of it will be 5 x 5 x (6.022x10^23) = 1.51x10^25 oxygen atoms.
18 atoms in total.
24 atoms in total
There is a total of 8 atoms in Ethane.
The number of atoms is seven.