To have a 50 / 50 mixture of antifreeze and preferably distilled water
you would need ( 7.5 liters / 7.9 quarts ) of antifreeze because according to the
Owner Guide the cooling system capacity is 15.0 liters / 15.8 quarts
Ford shows not to exceed 60 % antifreeze and not to drop below 40 % antifreeze in the cooling system
For a 1999 Lincoln Navigator : Assuming you want a 50 / 50 mixture of antifreeze and distilled water ( like it was from the factory ) With auxiliary rear heat ( approximately 14 U.S. quarts ) Without auxiliary rear heat ( approximately 13 ) * of antifreeze *
I was looking at the 1997 Lincoln Continental Owner Guide and the engine cooling system capacity ( including the heater ) is ( 14.25 quarts / 13.5 liters ) So , if you have a 50 / 50 mix of antifreeze and preferably distilled water You would need ( 7.125 quarts / 6.75 liters ) of antifreeze
it hold two(2) gallons of 50/50 antifreeze total
i believe its 20 qts. That is correct. 10 quarts of antifreeze and 10 quarts of distilled water.
About 2 gallons of a 50/50 mix of antifreeze and water
it can hold up to 6 ounces
13 quarts
9.9 litres
2 gallons
2 gallons
For a 1999 Ford F-150 ,4.6 L V8 : It came from the factory with a 50 / 50 mix of distilled water and GREEN color antifreeze ( meeting Ford specification ESE-M97B44-A ) 1 row radiator ( 10.3 U.S. quarts of antifreeze mixed with an equal amount of preferably distilled water ) 2 row radiator ( 11.55 quarts of antifreeze ) * Ford states not to exceed 60% antifreeze or drop below 40 % antifreeze in the mixture
Being an aircooled engine, the cooling medium is air .It does not need antifreeze