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First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
4 moles also 2 moles of oxygen will be consumed
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
6 moles
The answer is: 5 moles oxygen and 4 moles H2O.The reaction is:C3H8 + 5 O2 = 3 CO2 + 4 H2O
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
The total number of moles of NO produced when 1,0 mole of O2 is completely consumed is 2.
4 moles also 2 moles of oxygen will be consumed
0. Hydrogen doesn't "reackt" to form Nitrogen Monoxide.
12 moles KClO3 (3 moles O/1 mole KClO3) = 36 moles of oxygen.
6 moles
2 KClO3 ----> 2KCl + 3O2 So 2 moles of Potassium Chlorate produces 3 moles of oxygen molecules or 6 moles of oxygen atoms. 3 moles of Potassium chlorate would thus produce 4.5 moles of oxygen molecules or 9 moles of oxygen atoms.
Each mole of PbO2 contains 2 moles of oxygen (O). Thus there would be 5.43x2 = 10.86 moles O.Each mole of water (H2O) contains 1 mole of O, so from 10.86 moles of O you could get 10.86 moles of H2O.
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
If the reaction were 2AlCl3 + 3Pb ---> 3PbCl2 + 2Al, then from this balanced equation, 14 moles of AlCl3 would produce 3/2 x 14 moles of PbCl2 = 21 moles of PbCl2.
2s + 3o2 --> 2so3