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How much heat in joules is required to heat a 48 sample of aluminum from 73 to 140?
Wiki User
∙ 12y ago
you need the specific heat of aluminium
c = .9 J/(Kg*K)
140 +273 = 413 K
73 +273 = 346 K
413-346 = 67 k
c*T*m = .9 (J/(Kg*K) * 67 K * 48 Kg = 2894.4 J
Wiki User
∙ 12y ago
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specific heat(; your welcome!
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How much eat in calories is required to heat a 43 g sample of aluminum from 72 F to 145F?
How much heat (in calories) is required to heat a 43 g sample of aluminum from 72 F to 145F
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How many joules of energy are necessary to heat a sample of water with a mass of 46 g?
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