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How much heat is absorbed when 52.3 g H2O(l) at 100 and degC and 101.3 kPa is converted to steam at 100 and degC (The molar heat of vaporization of water is 40.7 kJmol.)?
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When are the quantites molar enthalpies of fusion and molar enthalpy of vaporation used?
Fusion refers to the phase change from liquid to solid (or vv) and vaporization refers to the phase change from liquid to gas (or vv). Heat is either absorbed or released from the substance when these events occur. We use the molar enthalpies to calculat exactly how much heat is transferred during these processes. Ex .. If we are to boil (vaporize) 3 moles of some substance with a known molar enthalpy of vaporization of 120 KJ/mole then we multiply. 3 moles x 120 KJ/mole = 360 KJ of energy is needed for the vaporization to take place.
What units does molar heat of vaporization have?
In SI units: kJ/kmol
What is the relation of the molar heat of fusion to the molar heat of vaporization?
Molar heat of fusion: the heat (enthalpy, energy) needed to transform a solid in liquid (expressed in kJ/mol). Molar heat of vaporization: the heat (enthalpy, energy) needed to transform a liquid in gas (expressed in kJ/mol).
What is the mass of hydrogen converted into moles?
The molar mass of hydrogen is 2 g.
Converting nmol to mg?
In order to convert mmol (millimoles) to mg (milligrams), you will need to know the molar mass of the chemical formula you want converted. The molar mass will vary depending on the chemicals used.
How many kilojoules of heat are absorbed when 0.38 g of chloroethane (C2H5Cl bp 12.3 and degC) vaporizes at its normal boiling point (The molar heat of vaporization of chloroethane is 26.4 kJmol.)?
The necessary heat is 0,155 kJ.
The molar heats of sublimation and fusion of iodine are 62.3kjmol and 15.3kjmol respectively calculate the molar heat of vaporization of liquid iodide?
It is a known fact : Molar heat of sublimation = molar heat of fusion + molar heat of vaporization so, molar heat of vaporization = molar heat of sublimation - molar heat of fusion Mv = 62.3 kJ/mol - 15.3 kJ/mol Mv = 47 kJ/mol.
When are the quantites molar enthalpies of fusion and molar enthalpy of vaporation used?
Fusion refers to the phase change from liquid to solid (or vv) and vaporization refers to the phase change from liquid to gas (or vv). Heat is either absorbed or released from the substance when these events occur. We use the molar enthalpies to calculat exactly how much heat is transferred during these processes. Ex .. If we are to boil (vaporize) 3 moles of some substance with a known molar enthalpy of vaporization of 120 KJ/mole then we multiply. 3 moles x 120 KJ/mole = 360 KJ of energy is needed for the vaporization to take place.
What units does molar heat of vaporization have?
In SI units: kJ/kmol
What is the relation of the molar heat of fusion to the molar heat of vaporization?
Molar heat of fusion: the heat (enthalpy, energy) needed to transform a solid in liquid (expressed in kJ/mol). Molar heat of vaporization: the heat (enthalpy, energy) needed to transform a liquid in gas (expressed in kJ/mol).
Why is the molar of vaporization for water higher than most other substances?
Because water has highly polar bonds between the water molecules. These create very strong bonds that keep the water molecules from evaporating until enough heat has been absorbed to break those bond and separate the molecules.
Estimate the molar heat of vaporization of a liquid whose vapor pressure doubles when the temperature is raised from 85 C to 95 C?
study
The vapor pressure of ethanol is 100 mmHg at 34.9oC and 400 mmHg at 63.5oC What is the molar heat of vaporization of ethanol?
39330 j.mol-1
The molar heat of fusion for water is 6.008 kJmol What quantity of heat energy is released when 253 g of liquid water freezes?
When the molar enthalpy of fusion for water is 6.008 kJ/mol, there is 84.4 kJ released when 253 grams of liquid water freezes. 84.4 kJ
What is the mass of hydrogen converted into moles?
The molar mass of hydrogen is 2 g.
10.0 moles of a liquid are converted to its vapor at its boiling point 100 K and at 1 ATM The molar heat of vaporization of the liquid is 200 kjmole at this T and P Calculate work and heat?
10 mol x 200 kJ/mol = 2000 kJ S = 20 kJ/K
What is called to the amount of energy needed to melt one mol a substance?
First things first: it's actually spelled "enthalpy", which might be why you're not finding it.If you want a number, you will need to specify a substance.If you just want to know what it means, then in simple terms it's the amount of energy required to evaporate one mole of the substance.
