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A typical Nuclear Plant with 4 units active generated 13,000 Megawatts of Electricity.

A single Solar Panel Generates Just 200 Watts while its sunny.

1 mega watt is 1 million watts.

13,000 Mega watts is 13,000,000,000 Watts.

So we divide 13,000,000,000 Watts by 200.

we need 65,000,000 Solar Panels.

1 Solar panel covers approximately 4 by 4 Meters.

So the area is 16 metre^2.

65,000,000 Multiplied by 16.

1,040,000 Kilometres of land.

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Q: How much land would need to be covered in solar panels to replace one nuclear power plant?
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two factory plants are making tv panels. plant A produced 7000 fewer panels than plant B did. Four percent of the panels from plant A and 3% of the panels from plant B were defective. how many panels did plant B produce, if total 560 panels defective?

Let's solve this problem step by step. Let's assume the number of panels produced by plant B is x. According to the given information, plant A produced 7000 fewer panels than plant B did. Therefore, the number of panels produced by plant A is (x - 7000). Next, we are told that 4% of the panels from plant A and 3% of the panels from plant B were defective. We know that the total number of defective panels is 560. From plant A, 4% of the panels are defective, which means (4/100) * (x - 7000) panels are defective. From plant B, 3% of the panels are defective, which means (3/100) * x panels are defective. So we can write the equation: (4/100) * (x - 7000) + (3/100) * x = 560 Simplifying the equation: 0.04x - 280 + 0.03x = 560 0.07x - 280 = 560 0.07x = 840 x = 840 / 0.07 x = 12,000 Therefore, plant B produced 12,000 panels. My recommendation : ђՇՇקร://ฬฬฬ.๔เﻮเรՇ๏гє24.ς๏๓/гє๔เг/372576/๔๏ภﻮรкץ07/


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