Want this question answered?
16 bits per block . 8 16bit blocks = 128bits
Rimm
If you assume that it has a 16-bit data bus, then it would be 128k so the microprocessor can access 2^16 points, which is 64k (from it being a 16bit address) 16bits = 2 bytes (memory) so through a 16 bit memory, it can access 2*64k, which is 128k alternatively, if its 8bit memory, 8bits=1byte 1*64k = 64k I'm no expert, and i was searching for the answer myself, hope this helped
Its 16bit microprocessor,and-> the 8086 has a 16bit databus 20bit address bus-> the intel 8086,is designed to operate in two modes namely(1) minimum mode(2) maximum mode
16bit refers to the number of bits that can be used in a single data format element. 16bit graphics are found in games that can be played on the original Nintendo Entertainment System console.
It is a 3 byte instruction, with one byte for opcode and the other two for the 16bit address. It takes four machine cycles (one to fetch opcode, one to fetch lower order address, one to fetch higher order address and another one to fetch the data from the memory)... i.e. it takes 13 time states to perform the LDA instruction
Standard VGA is 16bit.
The h-L register in computing refers to a pair of registers used in some processors to store a 16-bit memory address. It is often used for memory operations and calculations involving memory addresses. The h register stores the high-order byte while the l register stores the low-order byte of the address.
An instruction is a command to the microprocessor to perform a given task on specified data. Each instruction has two parts: One is task to be performed,called the operation code (opcode). Second is the data to be operated on, called the operand. It can be specified in various ways,it may include 8bit/16bit data, an internal register, a memory location , or 8bit/16bit address. In some instructions, the operand is implicit. The 8085 instruction set is classified into three groups according to Word size. They are- 1. One word / 1 byte instructions 2. Ttwo word / 2byte instructions 3. Three word / 3byte instructions
Which processor has a 32-bit Data Bus and a 24-bit Address Bus?
The Java compiler itself (javac) is a 32-bit application.
so they fit correctly into an 8bit or 16bit slot