It has both +3 and +2 oxidation states
+1 for H, -2 for each O, +3 for I
First O has an oxidation number of -2; K will an oxidation number of +1 as it is an alkali metal. Therfore the Mn is +6. note that while the manganate ion exists, the question may relate to the permanganate ion MnO4-, so KMnO4, where Mn has oxidation number of +7
oxygen is 2- so four oxygen have 8- charges therefore two Sb should have 8+ and therefore the oxidation number of Sb is 4+
oxidation number of I is -1. oxidation number of F is +1.
It has both +3 and +2 oxidation states
+1 for H, -2 for each O, +3 for I
First O has an oxidation number of -2; K will an oxidation number of +1 as it is an alkali metal. Therfore the Mn is +6. note that while the manganate ion exists, the question may relate to the permanganate ion MnO4-, so KMnO4, where Mn has oxidation number of +7
oxygen is 2- so four oxygen have 8- charges therefore two Sb should have 8+ and therefore the oxidation number of Sb is 4+
To calculate the oxidation state of fluorine in O2F2, first draw a diagram of the molecule: F-O-O-F Determine the most electronegative atom(s), which are fluorines -- the most electronegative atom there is. Being in the group 7A, a fluoride ion would gain an electron to a -1 charge, so each has an oxidation number of -1. The oxygens, therefore, have an oxidation number of +1 each.
oxidation number of I is -1. oxidation number of F is +1.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
The oxidation number determines how much an element is oxidated, so the oxidation number of...1. elements is always 0.2. of simple ions is always the charge, e.g. in Cu2+ the oxidation number of copper is +2.3. hydrogen is usually +1, oxygen usually -2, alkali metals +1, etc.In molecules without a charge, the sum of the oxidation numbers has to be 0. This way you can calculate the oxidation number of its compounds. For example in KMnO4, the oxidation number of oxygen is -2, of K is +1, so if the sum is zero then the oxidation number of Mn has to be +7.In complex ions (OH-, MnO4-, ...) the sum of the oxidation numbers has to be the charge of the ion. (so in OH- and MnO4- it's -1).
Zn has oxidation number +2; S has oxidation number -2
The oxidation number for H is +1, and the oxidation number for O is -1.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
Oxidation number of Si is +4.Oxidation number of O is -2.