#include <iostream.h>
#include <conio.h>
#include <stdlib.h>
int swap(int* , int*);
int main()
{
int c=0;
int b=1;
int max;
cout<<"Enter the maximum limit of fibbonacci series = ";
cin>>max;
if(max>0)
{
cout<<c<<endl;
}
else
{
exit (EXIT_FAILURE);
}
for(int i=0;i<max;i++)
{
c=b+c;
swap(&b,&c);
if(c<max)
{
cout<<c<<endl;
}
else
{
break;
}
}
getch();
return 0;
}
int swap(int *x,int *y)
{
int z;
z=*x;
*x=*y;
*y=z;
return z;
}
int array[10];
int i;
array[0] = 0;
array[1] = 1;
for (i=2; i<10; i++) array[i] = array[i-1] + array[i-2];
for (i=0; i<10; i++) printf ("%d\n", array[i]);
Warning: Fibonacci number grow large fast, and will overflow any fixed precision binary format. In the case of 32 bit signed binary numbers, the maximum term that can be generated is 47, array[46]
Fibonacci series has absolutely nothing to do with pointers.
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }
You mean you have written a program, but you don't understand it? Well, how could I explain it without seeing it?
public static int fib(int n) {return fib(n-1) + fib(n-2);}
//WAP to print fibonacci series using do-while loop.? using System; class Fibonacci { public static void Main() { int a=1,b=1; int sum=0; Console.Write("Enter Limit:"); int n=Int32.Parse(Console.ReadLine()); Console.Write(a); Console.Write(b); do { sum=a+b; a=b; b=sum; Console.Write(sum); } while(sum<n); } } By-Vivek Kumar Keshari
i dn't know. haha
What is the assembly program to generate a geometric series and compute its sum The inputs are the base root and the length of the series The outputs are the series elements and their sum?
subtract the smallest one
#include #include void main() { clrscr() int a=0,b=1,c,i,n; coutn cout
Exactly what do you mean by 'C program in Java'
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
//to generate Fibonacci series upto a range of 200....(in C).... #include<stdio.h> main() { int a,b,c,i; a=0; b=1; printf("\n FIBONACCI SERIES .....\t"); i=1; while(i<=(200-2)) { c=a+b; printf("\t%d",c); a=b; b=c; i++; } }
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }
You mean you have written a program, but you don't understand it? Well, how could I explain it without seeing it?
20 is not a term in the Fibonacci series.
There is no upper bound to the sum of the numbers in the Fibonacci sequence; both the last number in the series and consequently the sum of all these numbers can be made as large as desired by continuing the series to sufficiently many numbers.
Yes, this can be done. For example for Fibonacci series. You will find plenty of examples if you google for the types of series you need to be generated.