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1 mol of MgSO4.7H2O has 246,47 g.
moles of what?
5.56
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
The chemical formula of the anhydrous copper(II) sulfate is CuSO4. The molar mass is 159,609. The percentage of oxygen is 40,25 %, or 64,245 g.64,245 g oxygen (O2) is equal to cca. 2 moles.
This depends on: - if it is an anhydrous or hydrated salt - if it is a salt of Cu(I) or Cu(II) For CuSO4(anh.) the answer is 0,00364 moles.
1 mol of MgSO4.7H2O has 246,47 g.
The answer is 159,62 g for the anhydrous salt.
moles of what?
5.56
The mass in grams of 3,20 moles of copper is 158,865 g.
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
If you know moles of each use their molar masses to convert to mass.
This ratio is 1:2.
The chemical formula of the anhydrous copper(II) sulfate is CuSO4. The molar mass is 159,609. The percentage of oxygen is 40,25 %, or 64,245 g.64,245 g oxygen (O2) is equal to cca. 2 moles.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
5,25 moles (in anhydrous sodium sulphate)