1 mol of MgSO4.7H2O has 246,47 g.
Do you mean from this reaction? MgSO4 + 2H2O -> Mg(OH)2 + H2SO4 let us assume water is in excess 0.01246 MgSO4 (1 mole Mg(OH)2/1 mole MgSO4) = 0.01246 moles Mg(OH)2 produced ----------------------------------------------- This reaction is one to one.
0,75 moles of AlCl3 (anhydrous) is equivalent to 100,005 g.
400 grams of nickel sulphate (anhydrous) is equivalent to 2,58 moles.
471,6 g of anhydrous Ba(OH)2 is equivalent to 2,75 moles.
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
Molarity = moles of solute/Liters of solution5 M MgSO4 = moles MgSO4/1 L5 moles MgSO4=============since all is one to one in ion countMg 2+ = 5 moles--------------------------andSO4 2- = 5 moles----------------------
48.8 g MgSO4 & 51.2 g H2O Convert the mass into moles by dividing molar mass for each. Then obtain a ratio of moles of water over moles of Magnesium Sulfate, and you would get 7. MgSO4 . 7H2O would read as Magnesium Sulfate Heptahydrate.
First we calculate the formula mass of the compound magnesium sulfate.Formula mass of MgSO4 = 24.3 + 32.1 + 4(16.0) = 120.4 Amount of MgSO4 in a 480g pure sample = 480/120.4 = 3.99mol There is approximately 4 moles of the compound present in a 480g sample.
This depends on: - if it is an anhydrous or hydrated salt - if it is a salt of Cu(I) or Cu(II) For CuSO4(anh.) the answer is 0,00364 moles.
0.01362 moles.
Depends on if it is hydrated or not. If hydrated, magnesium sulfate heptahydrate, then (7.6g)/(246.47g/mole)=.0308mole. If anhydrous (7.6g)/(120.415g/mole)=0.063mole.
If you know moles of each use their molar masses to convert to mass.
Do you mean from this reaction? MgSO4 + 2H2O -> Mg(OH)2 + H2SO4 let us assume water is in excess 0.01246 MgSO4 (1 mole Mg(OH)2/1 mole MgSO4) = 0.01246 moles Mg(OH)2 produced ----------------------------------------------- This reaction is one to one.
5,25 moles (in anhydrous sodium sulphate)
1337
31,3 g sample of anhydrous CaSO4 equal 0,23 moles.
0,75 moles of AlCl3 (anhydrous) is equivalent to 100,005 g.