if the horn is already there and is bad, just disconnect the two wires on it, unscrew horn, remove it and reinstall the new one and reconnect the wires. If you don't have a horn, then find a suitable place under the hood and drill X number of holes. The switch is wired in series with the battery and horn. The button is placed at a convenient place you can get to it when you want to blow the horn.
The positive terminal of the battery would be connected to the positive terminal of the ammeter. The load would then be connected between the two negative terminals, positive side of the load being connected to the negative side of the ammeter.
a battery and a resistor connected together.
You would short out the battery. If it was a car battery capable of 300 amps and the wire was big enough, the battery could explode.
The voltmeter would read 12 volts. An ammeter connected to to battery would only read 4 amps (12 volts divided by 3 ohms =4)
it is possible for the unlock side of the switch to be bad and it has nothing to do with the battery
I am not completely sure on why you battery in your Mustang would be smoking only when connected to the starter. I would take into a shop and have them look at it.
Related to a battery and open load is the battery just sitting there without anything connected. A short is a very low resistance attached to the tow terminals of the battery. For example, a wire connected across the battery terminals would constitute a short.
That would be a battery.
Overcharging by the alternator or if it is connected in reverse polarity.
The energy delivered by a battery would depend on-- the battery's voltage-- the resistance of the load connected across its output terminals-- the length of the time the load is connectedThe power delivered by the battery is [ (voltage)2 divided by (load resistance) ].The total energy delivered by the battery is [ (power) multiplied by (time the load is connected) ].
nearly 12v when running means your battery is not getting charged.. it should be just shy of 14v when the alternator is working correctly
Torch equals flashlight. Battery negative connected to case switched to bulbs outside. Positive connected to the lamps bottom. Called a series circuit.
If the batteries are connected from + (positive) to - (negative) then the batteries are connected in "series". If the batteries are AA (1.5v each), then the resulting voltage of the two connected in series will be 3.0v. If the batteries are connected + to + and - to -, then they are connected in "parallel" and for the same batteries the voltage would be 1.5v, but would last twice as long as one battery by itself. A truck battery system is two 12v batteries connected in series (+ to -) to give the truck a running power of 24v.
depends on the voltage of the battery being used. USB voltage is 5 volts DC. If you use a car battery, which is generally 12 volts, I would think your device would not like this. But to answer your question. Yes, it will charge. But not properly if you do not use the correct voltage.
This would be an Electromagnet...... If the battery is disconnected, then the iron bar will become a permanent magnet.
No, the battery connected to an inverter would not have near enough power to run a dryer.
Also known as a Tycoon Buy button.
No, not from something pulling power from the battery. A battery that runs down with one cable disconnected has a dead cell and must be replaced.
i just connected my ac belt and there was a black wire that was disconnected from the battery and i attached it back to the battery
Year, make, model and engine size would help but if you follow the positive battery cable from the battery to the other end of it, it will be connected to the starter.
Sure you can. But it would be much easier to purchase a compacitor which acts like a battery in that it stores power and uses that to power what is connected to it. This also saves the alternator
Sounds like you need a new battery that works.
If they were in series in the circuit, they would act as on/off switches.
Maybe at the plug you did not switch it on =] If not I don't really know =]
Voltage would be that of 1 cell.