In a capacitive circuit, you must first calculate the capacitive reactance (Xc) This is done by 2 x Pi x frequency x the value of capacitor. Then divide one by the answer. This will give you the capacitive reactance in ohms. You can then apply ohms law to find the current. So eg: A 10 ohm resistor is in series with a 150micro farad capacitor across a 230v 50Hz supply. find circuit current. So 2 x pi x 50 x 150E-6(means x10-6 on calc) 2 x 3.14159... x 50 150e-6 = 0.047123889(ans) Now 1/Ans = 21.22 ohms. So you can now add the 21.22 ohms and the 10 ohms together giving 31.22 ohms. This is the total circuit resistance. Now apply ohms law I = V/R So I = 230/31.22 = 10.83 Amps!
You know if current is flowing in a bulb circuit because, if there is enough power (voltage times current), the bulb will illuminate. If there is current, but not enough power to illuminate the bulb, you will need to measure the current with an ammeter to see if there is any current.
The AC current grows gradually when an inductive circuit is switched on. This specific current, also know as a electromagnetic field, is slowly growing, then shrinking, and changing, because of the wire current.
The first thing you need to know is the internal resistance of the current source, the voltage source will have the same internal resistance. Then compute the open circuit voltage of the current source, this will be the voltage of the voltage source. You are now done.
The current is 0. Current is the unit of flow of electrons in a circuit, and in an open circuit, electrons cannot flow. Therefore there is 0 current. Another way to look at it is that I = V / R, where I = Amps (current), V = voltage, and R = resistance (impedance). In an open circuit, the impedance is infinite, and by using our math skills, we know that X (or V in our case) divided by infinity, is 0. I = V / Infinity = 0
Reading this question, one kind of has to guess what's being asked. Here's a statementthat may or may not be helpful to the questioner:A series circuit is one in which there's never a point where the current has to decidewhich path to take. There's never a point where the current can split, and there's onlyone possible route all the way through the circuit.In a series circuit, the magnitude of the current is the same at every point.
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A Galvanometer can be used to detect the presence of current in a circuit. An ammeter can be used to know the magnitude of the current flowing through the circuit.
No way of telling unless you know the current of all devices that use the circuit. The maximum wattage for the circuit, assuming a resistive load (no motors) would be: Watts = Volts x Current.
You know if current is flowing in a bulb circuit because, if there is enough power (voltage times current), the bulb will illuminate. If there is current, but not enough power to illuminate the bulb, you will need to measure the current with an ammeter to see if there is any current.
It is certainly an option, if you know the topic well - or if you like it and would like to explore it.
Series circuit: The total voltage is the sum of the voltage on each component. The total resistance is equal to the sum of the resistance on each component. The total current is equal in every component.
V=IR where V is voltage, I is current and R is resistance. You want to know what the current will be in a series circuit based on the resistance. You need to know the voltage as well as the resistance, gives you the equation as follows I=V/R So if you have 10 volts and a 1 ohm resistor, the current will be 10 amps. If you increase the resistor to 10 ohms, your current will then be 1 amp. In a parallel circuit, the resistance is equal to the sum of the inverse. For example. If I have two resistors of 2 ohms each in parallel, the equation would be 1/2 + 1/2 = 0.5 + 0.5 = 1 In that particular instance, your current would increase.
You'd need to know either the resistance or the wattage of the circuit. Ohm's Law: Current = Voltage divided by resistance or Current = Power divided by Voltage
The AC current grows gradually when an inductive circuit is switched on. This specific current, also know as a electromagnetic field, is slowly growing, then shrinking, and changing, because of the wire current.
The first thing you need to know is the internal resistance of the current source, the voltage source will have the same internal resistance. Then compute the open circuit voltage of the current source, this will be the voltage of the voltage source. You are now done.
Jam your finger in it. Or RTFM.
No. Current and voltage are directly proportional to one-another and both are related to resistance by Ohm's law: V = IR or Volts = Current * Resistance So the current will depend upon the voltage and the circuit resistance by rearranging the above equations: I = V/R Meaning that the current will decrease as circuit resistance is increased if the voltage remains constant.