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I = E/R If resistance is constant, then current is directly proportional to voltage. Double the voltage ===> the current will also double.
That has no effect on the resistance. The current doubles also.
The current is doubled.I = V/RI=2V/RLets assign arbitrary numbers to voltage and resistance to evaluate what happens. Voltage will be 8 volts and resistance will be 2 ohms.I = 8/2 Therefore current = 4ampsIf voltage is doubled then,I =2(8)/2I=16/2I = 8 amps
That depends on the components in the circuit: resistive, reactive, nonlinear, etc.
Impedance of a coil or a capacitor does depend on the excitation frequency,but resistance has no relationship to frequency.
It is halved. coz voltage=current * resistance
In an electrical circuit, if resistance is doubled, EMF (measured in volts) stays constant, and current is halved.
The current in the circuit will be decreased by half. Ohm's law states V=IR so, I=V/R. If R is doubled, then I= V/2R.
I = E/R If resistance is constant, then current is directly proportional to voltage. Double the voltage ===> the current will also double.
That has no effect on the resistance. The current doubles also.
it will cause a Short Circuit
by the ohms law we can clearly say that the current is the ratio of voltage to the resistance.as the resistance is doubled the current should be halved.
Using Ohms Law: V = I x R, where V (Voltage), I (Current), and R (Resistance). re-arranging: V/R = I Therefore if you double both the Voltage and the Resistance, the current remains unchanged.Current = Voltage / Resistance. If both resistance and voltage double the current remains the same.
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.
The answer depends entirely upon the scenario. Are you dealing with AC or DC? Does your circuit contain passive components or both passive and active components?For example, if you a simply dealing with a resistive DC circuit, you can derive your answer from Ohm's law, V = IR. Rearranging for current, I = V/R, so if you double the voltage, the current is subsequently doubled.
The current will increase and will flow more. If voltage increases, current must increase.