A 100 ohm, 3000 ohm, and 10000 ohm resistor in parallel has a total resistance of 95.8 ohms.
RParallel = 1 / Summationi=1toN (1 / Ri)
If they're connected in series the total resistance is 2000 ohms. If they're connected in parallel the resistance is 500 ohms.
The total resistance is 5 ohms. Scroll down to related links and look at "Parallel Resistance Calculator".
5 ohms
The equivalent resistance of 75 ohms and 150 ohms in parallel is(75 x 150)/(75 + 150) = 50 ohms
For an end-result of 10 ohms, you can have 1 resistance of 10 ohms, or 2 parallel resistance of 20 ohms each, or 3 resistances of 30 ohms each, etc.
In a parallel circuit, the total resistance is calculated as the reciprocal of the sum of the reciprocals of each individual resistance. So, for three resistances of 20 ohms, 20 ohms, and 10 ohms, the total resistance will be 1 / (1/20 + 1/20 + 1/10) = 1 / (0.05 + 0.05 + 0.1) = 1 / 0.2 = 5 ohms.
The equivalent total resistance of resistors connected in parallel is lower than the resistance of the smallest resistor. The general formula for calculating the total resistance of n resistors in parallel is Rt = 1 / (1/R1 + 1/R2 + ... 1/Rn) For two resistors in parallel, the formula simplifies to Rt = (R1 x R2) / (R1 + R2) If R1 = 10K ohms and R2 = 4.2K ohms, the total resistance of R1 in parallel with R2 is (10,000 x 4,200) / (10,000 + 4,200) = 2957.7 ohms. The total resistance is less than the smallest resistor (4.2K). For three resistors in parallel, the formula is Rt = 1 / (1/R1 + 1/R2 + 1/R3) If R1 = 100 ohms, R2 = 68 ohms, R3 = 1K ohm, the total resistance of these three resistors connected in parallel is: Rt = 1 / (1/100 + 1/68 + 1/1000) = 38.9 ohms The total resistance (38.9 ohms) is lower than the smallest resistor (68 ohms).
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms
5 ohms
In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
If two 1-ohm resistors are connected in parallel, their resistance is 0.5 ohms. If they are connected in series, their resistance is 2 ohms. It is not possible to connect only two resistors in series parallel.