Potassium hydroxide is the limiting reagent.
The answer is one mole.
Mg(BrO3)2 is magnesium bromate. Yes, it is a salt, but when hydolyzed in water, it will have a pH that is slightly basic. Why? Because it is formed from the reaction of a strong base, Mg(OH)2 and a somewhat weak acid HBrO3. Thus, a solution of this salt will have a pH >7
2 NaOH + MgSO4-----Mg(OH)2+Na2SO4 1 MOLE OF MgSO4 produce one mole of Mg(OH)2 SO 1 MWT OF MgSO4 PRODUCE1MWT OF Mg(OH)2 HENCE 120 GM MgSO4 PRODUCE 58 gm OF Mg(OH)2 and so on if x gm of MgSO4 PRODUCE y gm OF Mg(OH)2 x=(120*y)/58 ---- ----
I think what you mean is Mg(OH)2 vs MgO2H2. This is an ionic compound because it has a metal (magnesium). In it, Mg+2 is the cation (positive ion) and OH- is the anion. Because an ionic compound must have a zero net charge, there needs to be two OH- ions to cancel the +2 charge of the magnesium. so in the first formula it is shown that there are two OH- ions, but the second one is incorrect because OH is one ion and the elements are not separately written like that in an ionic compounds formula. hope this helps
Potassium hydroxide is the limiting agent.
The amount of Koh
The answer is one mole.
2
2NaCl + Mg(OH)2 --> MgCl2 + 2NaOH Make sure to put the parentheses around the hydroxide. There is a difference between Mg(OH)2 and MgOH2.
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
These compounds will not react. They both contain the same anion, and thus there can be no reaction between them. Consequently, the reactants will remain unchanged.
it is base
Mg + 2HCl → MgCl₂+ H₂ When a metal reacts with an acid a salt and hydrogen are produced.
Megnesium hydroxide is formed. molecular equation Mg(No3)2 + 2NaOH --> MgOH2 + 2Na(No3) complete ionic. Mg 2+ + (No3)2-2 + 2Na+2 + 2OH-2 --> MgOH2 + 2Na + No3+2 net ionic Mg 2+ + 2OH-2 --> MgOH2
Inorganic (no carbons)
Magnesium hydroxide