Yes it is molecular (or covalent) compound
325 g of CBr4 have 5,9.10e23 molecules.
Yes
No. CBr4 is nonpolar and H2O is polar. Both do not mix.
No, it is not.
No CBr4 is covalent.
Tetrahedral
Iron(III) bromide is an ionic compound.
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
There are no lone pairs and it's tetrahedral.
According to Avagadro's number one mole of any substance is equal to 6.022*10^23 particles. Knowing this you can calculate the number of atoms in 4.25 moles of carbon tetrabromide easily: 4.25(moles of carbon tetrabromide) * 6.022*10^23(atoms) = 2.559*10^24 So 2.559*10^24 atoms are present in 4.25 moles of carbon tetrabromide.
whenever carbon atom forms four covalent bonds the basic structure is tetrahedral because carbon in such cases is sp3 hybridized.
CBr4 , this is the correct formula for carbon-tetra-bromide
325 g of CBr4 have 5,9.10e23 molecules.
Yes
No. CBr4 is nonpolar and H2O is polar. Both do not mix.
No, it is not.
No CBr4 is covalent.