PbO2
86.62(8)%The molar masses of the constituent elements must be known.M(Pb) = 2.072(1) x 102 gmol-1M(O) = 1.59994(3) x 10 gmol-1From these and their respective molar ratios in the compound, the total molar mass of the compound must be calculated.M(PbO2) = M(Pb) + 2M(O)M(PbO2) = (2.072 x 10 gmol-1 + 2(1.59994 gmol-1)) x 10M(PbO2) = 2.392(1) x 102 gmol-1From the molar mass of the element in question and its ratio, and the compound, their total masses present in one mole of compound must be calculated.m = nMm(Pb) = 1 mol x 2.072 x 102 gmol-1m(Pb) = 2.072(1) x 102 gm(PbO2) = 1 mol x 2.392(1) x 102 g (always 1 mole)m(PbO2) = 2.392(1) x 102 gFrom these, the percentage of the element in question present in the compound can be calculated.m(Pb) x 100%/m(PbO2) = 2.072 g x 100%/2.392 gm(Pb) x 100%/m(PbO2) = 86.62(8)%
Lead oxides are: PbO, PbO2, Pb3O4, Pb2O3 and the possible Pb12O19.
Depending on the formula ! Two atoms in PbO2, three atoms in Al2O3, etc.
No its not polar
PbO2 is lead(IV) oxide.
‚Black!
The ionic chemical formula of lead(IV) oxide is: (Pb)4+ + 2 O-.
Pb + PbO2 + H2SO4 --> PbSO4 + H2O
Lead Dioxide or Lead IV Oxide
An ionic bond.
PbO2....Pb has a 4+ charge and therefore can be reduced to Pb2+ in PbO. Since it can be reduced it is an oxidizing agent.
Formula: PbO2
PbO2
PbO^2 is ionic.
PbO2
PbO2 + 4HBr ---- 2H2O + Br2 + PbBr2