The water pump is driven by the cam belt. This engine is an interference engine and as such it is critical that the cam belt be replaced correctly or severe engine damage will occur. In order to replace the water pump the cam belt must be removed. Unless you know what you are doing I suggest you take your car to a professional to have the water pump replaced and replace the cam belt at the same time. The cam belt must be replaced every 90,000 miles. If it breaks, severe engine damage will occur.
where is the water pump located on 1997 honda accord
How do you remove a water tube from a Honda accord 91 ex
In my '87 accord, replacing the water pump was a big ordeal at the shop - $550 was a bargain price for the job. it involved the same work as replacing the timing belt - which was only $50 extra at that point. Not that this is a specific answer, but the point is that it's hard. Rick
$325 to $425 is a reasonable price from an independent shop. $800 is reasonable at a Honda dealer. This will also include replacing the coolant.
Neither of those miles. If you have a 4 cylinder it has a chain and not a belt. The chain never needs replacing. If you have a V6 then Honda recommends replacing the cam belt and water pump at 105,000 miles.
The owners manual on a 2003 Honda Pilot (V6 engine) suggests replacing the timing belt at 105K miles as well as inspecting the water pump.
On the V6 change it and the water pump at 110,000 miles. On the 4 cylinder there is no belt but instead is a chain that never needs replacing.
The water temperature sensor on your 1991 Honda accord, is located on the front of the engine. The sensor is above the water thermostat housing.
need help on changing 95 Honda accord ex water pump and timing belt.
how to replace the water pump on a 1998 Honda Accord
Highly recommend while you are already there. Water pump will fail or leak before timing belt needs replaced again
Replacing the cam belt and water pump at a Honda dealer will cost around $900. Having it done by a trusted independent shop will run about 1/2 that.