If you put them in water, then they both separate and the chloried and nitrate switch places. It becomes Magnesium nitrate and lead chloride, one turns yellow and sinks while the other's clear and floats. I think. If you put them in water, then they both separate and the chloried and nitrate switch places. It becomes Magnesium nitrate and lead chloride, one turns yellow and sinks while the other's clear and floats. I think.
There is no reaction with metallic Lead (Pb) because Pb is more stable to oxidation then Mg-metal, which is the same as saying Mg2+ ions are stable compared to Pb2+, so they are not formed from the metallic Pb
When Magnesium is added to Lead nitrate solution, it will form Magnesium nitrate and Lead.. Odd question though.
The equation:
Pb(NO3)2 + Mg à Mg(NO3)2 + Pb
Produces Sodium nitrate and a precipitate of Lead iodide
MgCl2 (aq) +2 AgNO3 (aq) -------> Mg(NO3)2 + 2 AgCl (s)
There is a white precipitate of Silver I Chloride
When aqueous solutions of these compounds are mixed together yellow precipitates of Lead iodide are formed,
Pb(NO3)2 + MgI2 -----> PbI2 + Mg(NO3)2
Lead chloride and magnesium phosphate will be formed.
yes it would
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
double replacement
lead iodide crystals.. check this site out for the reaction answer.. http://en.wikipedia.org/wiki/Lead(II)_iodide
Produces yellow Lead(II) iodide and Sodium nitrate
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
A double displacement reaction.
double replacement
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
Lead(II) iodide and Sodium nitrate
It produces Potassium nitrate and Lead iodide
lead iodide crystals.. check this site out for the reaction answer.. http://en.wikipedia.org/wiki/Lead(II)_iodide
A precipitate of Lead iodide and Potassium nitrate are formed
Pour a solution of Sodium(or Potassium) Iodide over Lead nitrate solution. The Lead iodide will be precipitated out as a yellow solid
Produces yellow Lead(II) iodide and Sodium nitrate
A precipitation reaction occurs. Yellow precipitates of lead iodide are formed. The equation for this reaction is Pb(NO3)2 + 2KI -----> PbI2 + 2KNO3
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3