0. All electrons will pair if there is an even number
Diatomic oxygen has 6 valence electrons each and so has to share 2 pairs in order to satisfy the octet rule.
An oxygen molecule (O2), which is diatomic in its elemental form, has two O2- ions that form a covalent bond, which choose to double bond instead of single bond because they are more stable this way.
repulsive forces between unshared pairs of electrons
H-O-H Well, the hydrogens bring a total of two valance electrons to the mix and the oxygen contributes six, so the total valance electrons = 8 4 are used in the two bonds, so 8 - 4 = 4 Two lone pair, one above and one below the oxygen in the Lewis dot structure.
None. There will be two pairs (for a total of 4 electrons) on the Oxygen atom in the water molecule.
O2 shares two electron pairs, giving both oxygen atoms 8 electrons on the outer shell (noble gas configuration).
There are a total of eight. Two pairs are bond pairs and two are lone pairs.
A water molecule is made up of two atoms of hydrogen and one atom of oxygen. Oxygen atom has six electrons in its outer most shell and a hydrogen atom has one electron in its outer most shell. Oxygen and hydrogen atoms are unstable because they have less than eight electrons in their outer most shells. Oxygen needs two electrons and hydrogen atom requires one electron tocomplete their valence shell. Oxygen atom combines with two hydrogen atoms by sharingelectrons. The bonds present between hydrogen atoms and oxygen atom are called single covalent bonds. In this way, oxygen and hydrogen atoms complete their outer most orbits. Oxygen shares two electrons with hydrogen atoms but its four electrons remain free in the water molecule. Therefore, there are two electron pairs or four electrons present in a water molecule.
There are four electrons, which is two pair.
They share two pairs of electrons and have 2 lone pairs
First of all, what "are" the electrons in oxygen.Oxygen has 6 valence electrons (the electrons in the outer shell or in other words, the electrons that will react). Since every atom wants to have 8 valence electrons, then oxygen will want to gain 2electrons. Therefore it will use two of it's electrons to form bonds. Oxygen always forms two bonds with two lone pairs. :ö= or -:ö-
4
4 pairs
One chlorine-oxygen bond can be considered "Normal" with the oxygen donating one electron and the chlorine donating the other to form a covalent bond. Bonded to an oxygen atom in this manner, the chlorine atom has three nonbonding pairs of electrons. In order to achieve a stable, full outer shell, an oxygen atom needs to gain two electrons. So the chlorine donates its three pairs of electrons for bonding with three additional oxygen atoms.
These pairs of electrons are referred to as lone pairs.
lone pairs
The answer is not 6 as said here before! The number of valence electrons in O2 (oxygen molecule) is: 12 valence electrons. 6 of them from each oxygen (O) atom. 4 valence electrons make up the double bond between the two oxygen atoms, and the remaining 8 valence electrons form lone pairs (non-bonding pairs) on the oxygen atoms, 2 lone pairs on each. I hope there is some help in this.