Dihybrid cross
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Rr X Rr = 1RR, 2 Rr, and 1rr
Make two punnett squares- one for Yy x YY and one for rr x RR the possible outcomes for Yy x YY are: YY Yy the only outcome for rr x RR is Rr. so the gametes of the two could be either YY Rr or Yy Rr
A monohybrid cross is a cross between two individuals that are homozygous for different alleles of the same gene. An example is a cross between a red-eyed (RR) fruit fly and a white-eyed (WW) fruitfly.
In general, pink flowers tend to be an example of incomplete dominance of the gene for red flowers. Therefore, the phenotypic ratio of a cross between two pink flowers would be the same as the genotypic ratio of 1:2:1. In other words, 1 red to 2 pink to 1 white.
in a Bb x bb cross?
RR x rr
The cross RR X Dd is showing two different genes for the parents (it is showing RR for one parent and Dd for the other) - therefore this is not a dihybrid cross. However, if it was RRDd X RRDd, this would be a dihybrid cross. For a dihybrid cross, you need to include two different genes (and show these genes in both the parents). So - BbFf X bbff, GGTT X ggtt, KKPp X KkPp - are all examples of dihybrid crosses.
The cross would result In 50% pink and 50% white.
To figure this out, use a Punnet Square.First, set up a test cross, like this:Rr x rrThis shows what you are crossing. Now you can make a Punnet Square.R rr Rr rr There is a 50/50 chance that the corn plant will have thegenotype rr.r Rr rr
Lets start with using letters to symbolize each allele of each parent: Roan Bull x White Cow --> Rr x rr (where the alleles R = red and r = white). The resulting ratio of offspring is the following: Rr = 50% rr = 50% RR = 0% Since there are too many little "r"'s and not enough big "R"'s, we can only get a cross of white and roan calves to a ratio of 1:1. Red calves do not exist in this cross.
Let's say we're talking about red flowers (red=dominant, R allele) vs white flowers (white=recessive, r allele) If you cross two homozygous red flowers, RR x RR, you can only get RR offspring, or all red flowers. RR=genotype (what alleles, or genes, they have), red=phenotype (what they look like) To make the Punnett square, draw a 4-box diagram on a piece of paper by drawing a diagonal line and then a horizontal line halfway down so you get 4 squares. On the top of the box, put R R and along the left side, put R and then another R under it. To fill in the boxes for the Punnett square, cross the top left-hand gene (R) with the top gene on the left-hand side. You'll get RR. Do the same for the top right-hand gene (R) and the top gene on the side. You'll also get RR. Cross the bottom R with the left gene on the top (R) and the right gene on the top. All combinations will be RR in this example. If you had a red flower that had a homozygous genotype (RR) with a white flower, also homozygous (rr), the results are more interesting. When you draw your Punnett square, you'll see that you get one RR combination, two Rr combinations and one rr combination. This means that the F1 generation (offspring) will be: 25% homozygous red (RR) 50% heterozygous red (Rr) 25% homozygous white (rr) Put another way, you'll have one white flower and three red flowers, and two of those red flowers carry a gene for white which is not expressed because it is recessive.
If they are expressing the trait, 100%, as their genotypes would be, rr X rr If they both carry the trait and it is dominated, Rr X Rr, then the probability would be, 25% of their child expressing the trait.
Rr X Rr = 1RR, 2 Rr, and 1rr
Make two punnett squares- one for Yy x YY and one for rr x RR the possible outcomes for Yy x YY are: YY Yy the only outcome for rr x RR is Rr. so the gametes of the two could be either YY Rr or Yy Rr
RR X rr 100% Rr Heterozygous resistant for poison ivy.
vt x rr
Let RR = Red and WW = White and RW = PinkRR X WW = RW (all resulting flowers are pink)Punett Square of pink cross pink:RWRRRRWWRWWWAs you can see, 50% are pink, 25% are red, and 25% are white.This is an example of incomplete dominance in flower colour.