I think it wants to give up an electron
Two electrons are needed to fill the outer shell of a sodium atom. The outer shell for sodium is the 3s sublevel. A neutral sodium atom has one electron in its 3s sublevel. Since atoms undergo chemical bonding in order to gain a noble gas electron configuration, called an octet, sodium atoms will lose their single 3s electron, becoming sodium atoms with a 1+ charge. By doing this, sodium ions become isoelectric with the noble gas neon, and achieve an octet, becoming stable.
I think it is that there is only 1 electron in its outer shell.
Sodium has one electron in its outer ring.
Sodium only has one valence (outer shell) electron. It wants to fulfill the octet rule and have a full (8 valence electrons) outer shell. It could do this by adding 7 electrons to the one that's already there, or it could simply lose the one electron it has because the next shell is already full. But since it is "easier" for sodium to lose a single electron and requires the least amount of energy, this is what it does.
Sodium is in the third group in the periodic table. It meens that sodium has three shell. First shell - 2 electrons, second shell - 8 electrons, third shell (outer energy level) - 1 electron.
Each sodium atom will lose one electron to achieve a complete octet in its outer shell, as the octet rule dictates atoms will gain or lose electrons to achieve a stable electron configuration with 8 electrons in the outer shell.
Sodium conforms to the octet rule by losing one electron to achieve a full outer shell, becoming a positively charged ion. This electron loss allows sodium to reach a stable electron configuration similar to that of the nearest noble gas, achieving a more stable and lower energy state.
Two electrons are needed to fill the outer shell of a sodium atom. The outer shell for sodium is the 3s sublevel. A neutral sodium atom has one electron in its 3s sublevel. Since atoms undergo chemical bonding in order to gain a noble gas electron configuration, called an octet, sodium atoms will lose their single 3s electron, becoming sodium atoms with a 1+ charge. By doing this, sodium ions become isoelectric with the noble gas neon, and achieve an octet, becoming stable.
Sodium only has one electron in its outer energy level which it wants to lose in order to leave a stable octet of electrons in the level below. Loss of one electron causes a charge of plus 1 on the remaining ion.Magnesium has two electrons in its outer energy level, thus by losing these it takes on a charge of plus 2 and leaves a stable octet of electrons below in the next energy level.
1 electron which makes it belongs to group 1
A sodium atom has one electron in its outer shell.
Sodium atom is more stable than sodium ion because the atom has a full outer electron shell (valence shell) with 8 electrons, following the octet rule. In contrast, sodium ion has a positive charge and is less stable due to the loss of one electron from its outer shell.
I think it is that there is only 1 electron in its outer shell.
Sodium has one electron in its outer ring.
Sodium only has one valence (outer shell) electron. It wants to fulfill the octet rule and have a full (8 valence electrons) outer shell. It could do this by adding 7 electrons to the one that's already there, or it could simply lose the one electron it has because the next shell is already full. But since it is "easier" for sodium to lose a single electron and requires the least amount of energy, this is what it does.
No, sodium's outer shell is not stable because it only has one electron in its outer shell. Sodium will readily react with other elements to achieve a stable electron configuration by losing this electron.
it becomes a sodium cation