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The amount of grams in two moles depends on the element or compound that you have two moles of. For example, the molar mass of oxygen is about 16 grams. So two moles of oxygen would be about 32 grams.
Methane reacts with oxygen in the following way. CH4 + 3 O2 --> CO2 + 4 H2O. If 5 moles of oxygen react with 2.8 moles of methane, only 1.67 moles of methane would be consumed because of the molar ratio 1:3. This would produce 1.67 moles of carbon dioxide and 6.67 moles of water.
The number of grams in 4.56 moles of H2O2 would be 7.57. This is a math problem.
CH4 is the formula for methane
I mole - 16g of methane is 1 mole. At STP it would occupy 22.4 liters
2344222.445
Four times the atomic weight of carbon plus sixteen times the atomic weight of hydrogen = about 64 grams.
Taking carbon @ 12.01 g/mol & hydrogen @ 1.01 g/ mol methane has 1 carbon & 4 hydrogen, so it is:12.01g + 4(1.01g) = 16.05g per mole.For 4 moles: 4 x 16.05 g = 64.20 g
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
The molar mass of ammonia is about 17 grams, so that 3 moles would have a mass of 51 grams.
The mass would be approximately 92 grams.
92
The amount of grams in two moles depends on the element or compound that you have two moles of. For example, the molar mass of oxygen is about 16 grams. So two moles of oxygen would be about 32 grams.
224 grams of Oxygen will be in 2 moles of Potassium dichromate.
You can only calculate the empirical formula because you do not have a mass of this compound given. To do the empirical formula assume 100 grams and change percent to grams. Get moles. 80 grams Carbon (1 mole C/12.01 grams) = 6.66 moles C 20 grams hydrogen (1 mole H/1.008 grams) = 19.84 moles H the smallest becomes 1 in the empirical formula and the other number is divided by it, Thus; H/C 19.84 moles H/6.66 moles C = 2.9, which we call 3 so, CH3 --------------- is the empirical formula To get the molecular formula tour question needed to read; How to calculate molecular formula from such ans such mass of compound with these percentages of elements, Which, of course, your question did not provide. Then you would have divided that given mass by the mass total of the elements of the empirical formula, got a whole number by which you would have multiplied the numbers of your empirical formula to get molecular formula.
You would need to know the chemiscal formal for methane, X the numbers of mole.
The mass of 2 moles of ethyl alcohol would be 92,14 grams.