RT = 1 / summationK=1-N (1 / RK)
The total effecive resistance of several individual resistances in parallel is less than the smallest individual resistance, so in that sense I guess you'd have to say that the lowest resistance 'dominates' the character of the whole parallel circuit.
The rule for finding total resistance in a parallel circuit is that a parallel circuit has two or more paths for current to flow through. Another rule states that voltage is the same across each component of the parallel circuit. If one of the parallel paths is broken, current will still continue to flow in all the other paths.
Total equivalent resistance = reciprocal of (sum of reciprocals of each individual resistance)
The current in each individual component of the parallel circuit is equal to (voltage across the combined group of parallel components) / (individual component's resistance). The total current is the sum of the individual currents. ============================== Another approach is to first calculate the combined effective resistance of the group of parallel components. -- take the reciprocal of each individual resistance -- add all the reciprocals -- the combined effective resistance is the reciprocal of the sum. Then, the total current through the parallel circuit is (voltage across the parallel circuit) / (combined effective resistance of the components).
No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.No, it is less. Use the formula:1/R = 1/R1 + 1/R2 + 1/R3...Where R is the total (equivalent) resistance for the parallel circuit,and R1, R2, etc. are the individual resistance.
Not sure what you mean. The equivalent (total) resistance in a parallel circuit is less than any individual resistance.
No, the total resistance increases.
You raise the total resistance by that amount if added in series to a circuit. If you add them in parallel to a circuit then that total resistance will be less than the total of the added circuit.
No, series parallel, as it implies has components of the circuit configured in both series and parallel. This is typically done to achieve a desired resistance in the circuit. A parallel circuit is a circuit that only has the components hooked in parallel, which would result in a lower total resistance in the circuit than if the components were hooked up in a series parallel configuration.
You add up the currents in each branch. The current in each branch is just (voltage acrossd the parallel circuit)/(resistance of that branch) . ==================================== If you'd rather do it the more elegant way, then . . . -- Write down the reciprocal of the resistance of each branch. -- Add up the reciprocals. -- Take the reciprocal of the sum. The number you have now is the 'effective' resistance of the parallel circuit ... the single resistance that it looks like electrically. -- The total current through the parallel circuit is (voltage acrossd the parallel circuit)/(effective resistace of the parallel circuit) .
The total effecive resistance of several individual resistances in parallel is less than the smallest individual resistance, so in that sense I guess you'd have to say that the lowest resistance 'dominates' the character of the whole parallel circuit.
D. The total resistance is equal to the lowest resistance in the circuit
no
Does it? See Related Links
The rule for finding total resistance in a parallel circuit is that a parallel circuit has two or more paths for current to flow through. Another rule states that voltage is the same across each component of the parallel circuit. If one of the parallel paths is broken, current will still continue to flow in all the other paths.
Total equivalent resistance = reciprocal of (sum of reciprocals of each individual resistance)
The current in each individual component of the parallel circuit is equal to (voltage across the combined group of parallel components) / (individual component's resistance). The total current is the sum of the individual currents. ============================== Another approach is to first calculate the combined effective resistance of the group of parallel components. -- take the reciprocal of each individual resistance -- add all the reciprocals -- the combined effective resistance is the reciprocal of the sum. Then, the total current through the parallel circuit is (voltage across the parallel circuit) / (combined effective resistance of the components).