its 7
pOH = 14 - pH 5 = 14 - pH 9 = pH
The pOH is 6,4.
I will assume you are asking about the pH of pure water if pKw is 14.26. The relationship between pH, pOH, and pKw is as follows: pH + pOH = pKw. If it is pure, neutral water (no acids or bases present), then pH = pOH, so: pH + pOH = 14.26 2(pH) = 14.26 pH = pOH = 7.13
The pOH is 6,4.
ONLY in pure water at 25 0C :pH + pOH = 14.00
pH + pOH =14
To find the pOH of a solution when the H concentration is 1.7 x 10^-9 M, you can first calculate the pH using the formula: pH = -log[H+]. Then, you can find the pOH by subtracting the pH from 14, since pH + pOH = 14 in water. So, if the H concentration is 1.7 x 10^-9 M, the pH is 8.77, and the pOH is 14 - 8.77 = 5.23.
First, since NaOH is a base you have to find the pOH first so you use the equation -> pOH = -log[NaOH] pOH = -log[NaOH] = -log[0.0111] pOH = 1.955 Then you use this equation -> 14 = pH + pOH to find the pH 14 = pH + pOH pH = 14 - pOH = 14 - 1.955 pH = 12.045 and that makes it basic Hope that helped. ^_^
It will have a pOH of 12. Because pH+pOH=14
1.8
3
The pOH is 8,7.