The spectator ions are chloride and ammonium; the copper and phosphate ions precipitate from the solution as copper (II) phosphate.
cucl2 answer D
Ba2+ (aq) + SO42- (aq) → BaSO4 (s)
+2 for Copper(II)
15.0
You need the Ksp of copper sulphide. From that you can use the equation for solubility product - Ksp = [Cu2+].[S-] where the Cu2+ term becomes 25M.
No copper (II) chloride is an ionic compound.
Copper(II) chloride is already a compound; its formula is CuCl2
The chemical formula (not equation) of copper(II) chloride is CuCl2.
cucl2 answer D
Ba2+ (aq) + SO42- (aq) → BaSO4 (s)
They are identical - bonding two elements to form a binary compound. The only difference is that copper can be found as copperII or copperIV so it's correct to specify which one, that's all. Save with Pb (lead) and other unique metals/nonmetals.
CuOH2
Formula: CuI2
+2 for Copper(II)
PbCu2
The Transition metals can have variable charges depending on what they are bonded to. In this example the Copper atom is deficient by two electrons one for each Chlorine atom.
Formula: Cu(OH)2