It is a combusion.Water and CO2 is produced
It is an ignition reaction.It will produce CO2 and water.
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
CH4 like O2 is a gas that doesn't have a smell.But because of its chemical properties,specifically the ability to burn and explode, it was impregnated artificially with the smell of another substance called mercaptan.
No methane wont burn in oxygen free atmosphere Because you need oxygen to burn Methane. Methane by itself, even in the presence of lightning and comet strikes, is a perfectly safe gas. so methane does not burn in absence of oxygen Vishal Rijhwani
CH4 + 2 O2 -> CO2 + 2 H2O So for every L of CH4 you need 2 L of O2 So for 50L of CH4 you need 100L O2
It is an ignition reaction.It will produce CO2 and water.
To burn blue flames at least twice as much O2 is needed to burn one measured volume of natural gas CH4.CH4 + 2 O2 --> CO2 + 2 H2O
CH4 + 2O2 gives CO2 and 2H2O.So 16g of CH4 react with 64g of O2.So 24g react with 96g of O2
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
CH4 like O2 is a gas that doesn't have a smell.But because of its chemical properties,specifically the ability to burn and explode, it was impregnated artificially with the smell of another substance called mercaptan.
CH4, the chemical formula for Methane, is not inert. This is because it is very flammable and reacts readily with oxygen (combustion) according to the reaction: CH4 + O2 ---> CO2 + H2O + A lot of heat However, if you try to burn pure methane, you will not get the chemical reaction listed above. In fact, if you tried to light pure methane with a candle, the gas would just snuff out the candle. This "snuffing-out" can be misunderstood as CH4 being inert, or not reacting to the presence of heat.
No methane wont burn in oxygen free atmosphere Because you need oxygen to burn Methane. Methane by itself, even in the presence of lightning and comet strikes, is a perfectly safe gas. so methane does not burn in absence of oxygen Vishal Rijhwani
Take the balanced equation. CH4+2O2---->CO2+2H2O.So 2.8mol of CH4 need 5.6mol of O2.So O2 is limitting factor
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
When 85.0 g of CH4 are mixed with 160. g of O2 the limiting reactant is __________. CH4 + 2O2 → CO2 + 2H2O