Polonium 210-----------alpha particles-----------Lead 206
Polonium 209-----------alpha particles-----------Lead 205
Polonium 208-----------alpha particles-----------Lead 204
Polonium 214-----------alpha particles-----------Lead 210
Polonium 218-----------alpha particles-----------Lead 214 (99,98 %)
Polonium 218-----------beta particles------------Astatin 218 (o,o2 %)
For other isotopes see the list at: http://en.wikipedia.org/wiki/Polonium#Isotopes
An atom of polonium changes into an atom of lead after it emits an alpha particle. This transformation occurs as a result of radioactive decay, where the polonium nucleus loses two protons and two neutrons, transforming it into a lead nucleus.
Lead Pb
The daughter product that remains after the alpha decay of polonium-212 is lead-208. During alpha decay, polonium-212 loses an alpha particle, consisting of two protons and two neutrons, resulting in the transformation to lead-208.
Polonium is a natural radioactive element.
Polonium itself is not explosive. It is a radioactive element that can spontaneously decay, emitting alpha particles. However, polonium can be used to trigger a fission reaction in a nuclear bomb as part of a beryllium-polonium initiator.
Polonium-210 is an example of a radioisotope that emits alpha particles.
To write a balanced nuclear equation for the formation of polonium-206 through alpha decay, start with the parent nucleus, which is radium-210. Radium-210 undergoes alpha decay, emitting an alpha particle (helium nucleus) to form polonium-206 and an additional particle (usually a neutrino). The balanced nuclear equation for this process would be: (^{210}{88}Ra \rightarrow ^{206}{84}Po + ^4_{2}He).
Yes, even after an alpha particle is emitted, the atom remains the same element. The atomic number, which determines the element's identity, is based on the number of protons in the nucleus. So the atom would still be polonium with atomic number 84, but the resulting atom would have 2 fewer protons and 2 fewer neutrons due to emitting an alpha particle.
The reaction is:Po-210------------alpha particle------------------Pb-206
Polonium-210 become lead-206 after the emission of an alpha particle.
Polonium-210 lose an alpha particle and become lead-206.
The isotope radon-198 will alpha decay to polonium-194 as shown here: 86198Rn => 24He + 84194Po The radon is shown on the left, and the alpha particle, which is a helium nucleus, is shown of the right with the polonium.
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
When a polonium-216 nucleus undergoes alpha decay, it will lose an alpha particle, which is made up of 2 protons and 2 neutrons. This means that polonium-216, which has an atomic mass of 216 and an atomic number of 84, will become the element with the atomic number of 82 (84 minus 2), and will have an atomic mass of 212 (216 minus 4). Lead has an atomic number of 82. So, this is how polonium-216 becomes an isotope of lead when it emits an alpha particle.
The reaction is:Po-216----------------alpha particle-----------------Pb-212
It is alpha decay. In the process, an alpha particle(He2+) is released. So, it is called alpha decay.
The element with atomic structure similar to an alpha particle is helium. An alpha particle consists of two protons and two neutrons, the same as the nucleus of a helium atom.
alpha particle, He nucleus
Yes and no, alpha particles are a form or radiation (a helium nucleus), they are emitted from an unstable radioactive element which decays (and turns into some lighter element) by emitting the alpha particle. This form of decay is called alpha decay.