Any reaction occur.
The white precipitate formed in the reaction between BaCl2 and K2CrO4 is BaCrO4 (barium chromate). This precipitate forms because Ba2+ ions from BaCl2 react with CrO4^2- ions from K2CrO4 to produce an insoluble compound that falls out of solution.
sodium carbonate and barium chloride react to form sodium chloride and barium carbonate Na2CO3 +BaCl2 -------> 2NaCl +BaCO3
When BaCl2 reacts with HCl, a double displacement reaction occurs where the Ba2+ and Cl- ions from BaCl2 switch places with the H+ and Cl- ions from HCl, forming BaCl2 and HCl. The resulting products are BaCl2 and HCl.
The anhydrous barium chloride has an orthogonal crystalline structure.
To balance the reaction between silver and barium, you first need to determine the chemical formulas of their compounds. Silver forms Ag+ ions while barium forms Ba2+ ions. When they react, they form silver nitrate (AgNO3) and barium chloride (BaCl2). The balanced equation is 2AgNO3 + BaCl2 -> 2AgCl + Ba(NO3)2. This is a double displacement reaction.
When barium chloride (BaCl2) reacts with fluorine (F2), it forms barium fluoride (BaF2) and chlorine gas (Cl2). The balanced chemical equation for this reaction is: BaCl2 + F2 -> BaF2 + Cl2.
The equation is straight forward. One mole will react with one mole. So how many moles are in 34ml of .113M BaCl2? 0.113 / 1000, x 34 is 0.003842 moles BaCl2. So we now need to find out how many ml of Na2SO4 is 0.003842 moles. dividing 0.218 by 1000 tells you the amount of moles in 1 ml. i.e. 0.000218 moles. 0.003842/0.000218 = 17.624 ml needed to react.
Heating NaOH before adding BaCl2 helps to dissolve NaOH completely in water, ensuring that no solid NaOH remains undissolved in the solution. This is important because the reaction between BaCl2 and NaOH requires the NaOH to be in solution to react with the BaCl2. Heating the solution can also speed up the reaction between NaOH and BaCl2.
first of all, you need to recognize that one mole of Na2SO4 is reacting with one mole of BaCL2. so find the moles of the NaSO4, then you automatically have the moles of the BaCL2. if you get the moles of the BaCL2, its easy to calculate the volume of it because you already have the MOLARITY. good luck
The balanced chemical equation for barium chloride (BaCl2) reacting with potassium sulfate (K2SO4) is: BaCl2 + K2SO4 -> BaSO4 + 2KCl. This reaction forms barium sulfate (BaSO4) and potassium chloride (KCl).
This equation does not balance because 2 chlorine salts do not react with eachother. However, they are both highly soluable in water. By adding H2O, this equation can be balanced.
BaCO3+2HCl = BaCl2+CO2+H2O