potassium nitrate (aq) and lead iodide (s) are formed to create a yellow cloudy substance in a yellow liquid that will settle as a powder.
The observation will be a yellow precipitate of lead iodide, but if there is a higher chloride concentration, it will form a complex, hence a clear solution.
It produces Potassium nitrate and Lead iodide
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Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium nitrate and a precipitate of Silver iodide are formed
A precipitate of Lead iodide and Potassium nitrate are formed
Silver iodide (AgI), a precipitate insoluble in water, don't react with potassium nitrate.
It produces Potassium nitrate and Lead iodide
Ag(NO3)(aq) + KI(aq) ---> K(NO3)(aq) + AgI(s)
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The products are Mercury(II) iodide and Potassium nitrate
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Potassium nitrate and a precipitate of Silver iodide are formed
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
A precipitate of Lead iodide and Potassium nitrate are formed
Lead iodide (Pb2I) precipitates as a yellow solid, leaving a solution of potassium and nitrate ions.
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)