Do you mean "What is the chemical equation for those chemicals"? If yes, simply: 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 But if it is not, please clear your question.. :)
potassium chloride which is a type of salt and hydrogen gas and possibly something else but i am not sure.
There is no reaction. H+ + Cl- + K+ + I- --> 0000
There will be no precipitation in this reaction. Although, the two solutions will dissolve in each other, and would form a mixture of these two reagents.
Iodine is formed color of solution changes orange to green.
makes KCl and HI
A reaction doesn't occur.
Cl2 + 2KI --> 2KCl + I2
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
potassium iodide
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
A reaction doesn't occur.
potassium
Pb2+ + I- --> PbI2(s)potassium and acetate ions are left out of the equation, because they don't react (stay unchanged in solution)
2KI + F2 ----> 2KF + I2
Cl2 + 2KI --> 2KCl + I2
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.
H2O2 + 2 KI --> 2 KOH + I2
you have to write... 2KI + Cl2 = 2KCl + I2
2KI + Cl2 = 2KCl + I2
Br2 + (2e)- --> 2 Br- 2I- --> I2 + (2e)-
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
Cl2(g) + 2KI(aq) arrow 2KCl(aq) + I2(s)