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0,6 M of sodium chloride is 35,064 g.
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What is the molarity of a 2.000 L solution thatis made from 14.60 g of NaCL?
Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------
What is the molarity of a solution consisting of 0.250 mol NaCl dissolved in 2.25 L of solution?
Molarity = moles of solute/Liters of solution Molarity = 0.250 moles NaCl/2.25 Liters = 0.111 M NaCl --------------------
How much NaCl precipitate would be produced if 2 molarity HCl and 1 molarity sodium carbonate react in the reaction Na2CO3 plus 2HCL yeilds 2NaCl plus H2O plus CO2?
The resulting product would be a roughly 2 M NaCl solution (slightly less than 2 molar because the solution is diluted by the water that is produced by the reaction). 2 M HCl + 1 M Na2CO3 --> 2 M NaCl + 1 M H2O + 1 M CO2 Two moles of NaCl weigh about 117 g (58.5 grams per mol) so the resulting solution has a sodium chloride concentration of about 117 grams per liter. This concentration is well below the maximum solubility of water at room temperature and atmospheric pressure ( > 300 g/liter) so there would not be any NaCl at all precipitating. The answer is thus: no NaCl precipitate will form.
What is is the molality of 3.00 of NaCL and 1.50kg?
m = moles/kg = 3.00/1.50 = 2.00 molal
How do you calculate the molarity of the solution of 17.52 grams of Na Cl in a total volume of 2000 ml of solution?
Need moles NaCl first. 17.52 grams NaCl (1 mole NaCl/58.44 grams) = 0.29979 moles NaCl =====================Now. Molarity = moles of solute/Liters of solution ( 2000 ml = 2 Liters ) Molarity = 0.29979 mole NaCl/2 Liters = 0.1499 M NaCl ----------------------
What is 5 M of NaCl equivalent to?
5 M of NaCl is equivalent to 292,2 grams.
Which will have the lowest boiling point pure water 0.5 M NaCl aq 1.0 M NaCl aq or 2.0 M NaCl aq?
Pure Water
Calculate the isotonic coefficient for NaCl if a 07M of NaCl solution equaled the hemolysis of14M glucose solution?
i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2
preparation of 0.1 m of NaCL ML SOLUTION AND ITS LAP REPORT?
A solution of NaCl 1 M.
What is the total dilution factor from 1.00 M NaCl to 1.00 M NaCl solution?
The concentration is the same !
If 400.0 mL of 0.420 M NaCl are mixed with 110.0 mL of 0.240 M NaCl what is the molarity of the final solution?
In 400 ml of the 0.420 M NaCl there are 0.1680 moles of NaCl.In 110 ml of the 0.240 M NaCl there are 0.0264 moles of NaCl.There are 0.1944 moles of NaCl in 510 ml of solution. Dividing 0.1944 moles by 0.510 l gives 0.381 mole/l.So You get a 0.381 M NaCl.
5 percent NaCl equals x M NaCl?
5 % NaCl is equal to 5 g NaCl in 100 g of a material.
How many milliliters of 2 M NaCl solution are required to make 1 liter of 0.4 M NaCl solution?
200 milliliters
Which of the aqueous solution has the highest boiling point?
A. 0.25 M NaCl B. 0.5 M NaCl C. 1.0 M NaCl D. 1.5 M NaCl E. 2.0 M NaCl
What is the concentration M of a NaCl solution prepared by dissolving 3.8 g of NaCl in sufficient water to give 245 mL of solution?
Get moles NaCl and change 245 ml to 0.245 Liters. 3.8 grams NaCl (1 mole NaCl/58.54 grams) = 0.0650 moles NaCl Molarity = moles of solute/Liters of solution Molarity = 0.0650 moles NaCl/0.245 Liters = 0.27 M NaCl ----------------------
How could you make a 1.00M solution if you had a 2.00M solution of NaCl?
If we add 1 L of water to 1 L of 2 M NaCl solution will give 2 L of 1 M NaCl solution
How many moles per mL of the solute are contained in the 0.20 M NaCl?
0.0002 mol NaCl/mLmolarity = (moles solute)/(L of solution)0.20 M NaCl = 0.20 mol NaCl/L1 L = 1000 mL0.20 mole NaCl/1000 mL = 0.00020 mol NaCl/mL (rounded to two significant figures)
