5 M of NaCl is equivalent to 292,2 grams.
5 % NaCl is equal to 5 g NaCl in 100 g of a material.
0,16 mg NaCl is equivalent to 2,7.10-5 mol.
5 x 0.25 = 1.25 moles
Pure Water
0.02/5=0.004
i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2 i = isotonic molar [glucose] / isotonic molar [NaCl] i = 14 M / 7 M = 2
A solution of NaCl 1 M.
The concentration is the same !
In 400 ml of the 0.420 M NaCl there are 0.1680 moles of NaCl.In 110 ml of the 0.240 M NaCl there are 0.0264 moles of NaCl.There are 0.1944 moles of NaCl in 510 ml of solution. Dividing 0.1944 moles by 0.510 l gives 0.381 mole/l.So You get a 0.381 M NaCl.
Since 1 m is equivalent to 100 cm, 5 m is equal to 500 cm.
2M NaCl is a equivalent to a solution with 116,88 g NaCl in 1 L water.
5 + n