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The voltage across a resistance is in phase with the current through the resistance because the resitance in non-reactive, i.e. non-inductive and non-capacitative. In the inductive case, the load resists a change in current. In the capacitative case, the load resists a change in voltage. In the resistive case, the load current follows the voltage with no delay, hence there is no phase differential.
The amount of phase shift depends on the resistance that is also present in the system. In an ideal situation, the phase shift would be +90 degrees, but that would require a voltage source with zero resistance, conductors with zero resistance, and an ideal capacitor that exhibited only capacitance.
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
There is phase to phase voltage in 3 phase system.AnswerYou don't get voltage 'phase-to-phase'; it's 'line-to-line'!
The voltage is gained by multiplying the current and resistance together, i.e.. 50 x 500 = 25000 Imagine the three as a triangle with the voltage at the top, and the current and resistance at the bottom- V . ---- . I x R The voltage divided by the current is the resistance and the voltage divided by the resistance is the current. Therefore the current times the resistance is equal to the voltage. Having any two of these figures allows you to find the third.
The voltage across a resistance is in phase with the current through the resistance because the resitance in non-reactive, i.e. non-inductive and non-capacitative. In the inductive case, the load resists a change in current. In the capacitative case, the load resists a change in voltage. In the resistive case, the load current follows the voltage with no delay, hence there is no phase differential.
in a circuit of pure Resistance (r), IE. voltage source (12 v DC battery) and pure resistance (a light bulb). the voltage (v) and current (i) will be in phase. by adding capacitors and/or inductors to the circuit V and I will be pulled out of phase.
a. the current and voltage in phase
If current and voltage of an AC are in phase, then the "power factor" is 100%, and the load is a pure resistance, with no inductive or capacitive reactance (at least at the operating frequency of the AC).
The amount of phase shift depends on the resistance that is also present in the system. In an ideal situation, the phase shift would be +90 degrees, but that would require a voltage source with zero resistance, conductors with zero resistance, and an ideal capacitor that exhibited only capacitance.
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
The phase angle between voltage and current in a purely inductive circuit, under ideal circumstances where there is no resistance at all, is 90 degrees.
There is phase to phase voltage in 3 phase system.AnswerYou don't get voltage 'phase-to-phase'; it's 'line-to-line'!
The voltage is gained by multiplying the current and resistance together, i.e.. 50 x 500 = 25000 Imagine the three as a triangle with the voltage at the top, and the current and resistance at the bottom- V . ---- . I x R The voltage divided by the current is the resistance and the voltage divided by the resistance is the current. Therefore the current times the resistance is equal to the voltage. Having any two of these figures allows you to find the third.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)