From an experiment I did in my chemistry lab, I got a value of 52.0 kJ. But I have no idea what the "true" Ea is.
the reaction between bleach anb potassium iodide is KI+NaCl2--->KCl2+NaI
No reaction.
Produces Silver iodide precipitate and Sodium nitrate
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
double replacement
copper iodide
No reaction because the anion is common in both compounds.
There is no reaction, because silver iodide is very insoluble.
the reaction between bleach anb potassium iodide is KI+NaCl2--->KCl2+NaI
It's called a catalyst. A catalyst is present during a chemical reaction but does not participate as a reactant or product. A catalyst lowers the reaction's activation energy, making the reaction easier to happen. In the equation for a chemical reaction, the catalyst's formula appears in small notation above the "yield" arrow (format won't let me show you an example.) An example of a catalyst is potassium iodide (KI) speeding up the decomposition of hydrogen peroxide (H2O2).
Please mention this reaction.
No reaction.
Produces Silver iodide precipitate and Sodium nitrate
vanadium (III) sulfate + barium iodide =>
No, reaction
A double displacement reaction.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.