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well first you going to divide 32 by 12 and get 2. 66 repeat amps.

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Q: What is the current through the headlight circuit if the headlight on your mom's car has a resistance of 32 ohms and the car battery put out 12V?
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If you have a circuit consisting of a battery and a wire What two factors determine the amount of current in the circuit?

The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).


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That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.


If the headlight on your mom and car has a resistance of 32 ohms and the car battery put out 12v what is the current through the headlight circuit?

well first you going to divide 32 by 12 and get 2. 66 repeat amps.


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What is lost volts?

A battery is rated to supply a certain number of volts. However, it actually supplies less, because they are "lost" as the current has to get out of the battery in the first place.(The battery has internal resistance)The amount of lost volts depends on the current being drawn:The less resistance a circuit has, the more current is drawn, because it's easier to flow.Example:If the circuit has little resistance, it draws a large current and the battery's internal resistance causes more lost volts.If the circuit has high resistance, it draws a small current and there are fewer lost volts.This is why when you short-circuit a battery (give it hardly any resistance to go through) it heats up and may explode. A large current is drawn and all the volts are used by the battery's internal resistance.


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The resistance of the load is what causes an electric current to flow in a circuit.


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How much current is in a circuit that includes a 9-volt battery and a bulb with a resistance of 12 ohms?

Current = voltage/resistance If those are the only components in the circuit, then Current = 9/12 = 0.75 Ampere = 750 mA


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