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Density = mass(in grams)/volume(in cc or mL)

So, we need to get moles CO2 here with the ideal gas equation. ( 43 L = 43,000 mL and 30o C = 303.15 K, for next part )

PV =nRT

(2.1 atm)(43 L) = n(0.08206 L*atm/mol*K)(303.15 K)

n = 90.3/24.876

= 3.63 moles CO2

=============, Now, find grams CO2.

3.63 moles CO2 (44.01 grams/1 mole CO2)

= 159.756 grams CO2

================Now, to find density CO2.

Density = 159.756 grams/43,000 mL

[= 3.7 X 10 -3 g/mL]

==================Final answer. Seems quite reasonable.

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10y ago
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Q: What is the density of 43L of CO2 gas at 2.1atm and 30 degree celsius?
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